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If the first and the nth term of a G.P. are a ad b, respectively, and if P is the product of n terms, prove that P2 = (ab)n. - Mathematics

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प्रश्न

If the first and the nth term of a G.P. are a ad b, respectively, and if P is the product of n terms, prove that P2 = (ab)n.

योग
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उत्तर

Let the geometric series be a common ratio.

First term = a, nth term = ar n – 1 = b

P = product of n terms

= a. ar. ar2. ar3 …. arn – 1

= `"a"^"n". "r"^ (1+ 2 + 3 + ... +("n" - 1))`

= `"a"^"n""r"^(("n"("n" - 1))/2)`

p2 = `"a"^(2"n") "r"^("n"("n" - 1))`   ..........(i)

(ab)n = `("a" xx "ar"^("n" - 1))^"n"`

= `("a"^2 xx "r"^("n" - 1))^"n"`

= `"a"^(2"n"). "r"^("n"("n" - 1))`    ..........(ii)

From equations (i) and (ii),

P2 = (ab)n

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अध्याय 9: Sequences and Series - Exercise 9.3 [पृष्ठ १९३]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 9 Sequences and Series
Exercise 9.3 | Q 23 | पृष्ठ १९३

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