हिंदी

For a G.P. a = 2, r = -23, find S6

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प्रश्न

For a G.P. a = 2, r = `-2/3`, find S6

योग
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उत्तर

a = 2, r = `-2/3`

Sn = `("a"(1 - "r"^"n"))/(1 - "r")`, for r < 1

S6 = `(2[1 - (-2/3)^6])/(1 - (-2/3)`

= `(2[1 - (2/3)^6])/(5/3)`

= `6/5[(729 - 64)/3^6]`

= `6/5[665/729]`

S6 = `266/243`

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अध्याय 2: Sequences and Series - Exercise 2.2 [पृष्ठ ३१]

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बालभारती Mathematics and Statistics (Arts and Science) Part 2 [English] Standard 11 Maharashtra State Board
अध्याय 2 Sequences and Series
Exercise 2.2 | Q 2. (i) | पृष्ठ ३१

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