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If Pth, Qth, Rth and Sth Terms of an A.P. Be in G.P., Then Prove that P − Q, Q − R, R − S Are in G.P.

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प्रश्न

If pth, qth, rth and sth terms of an A.P. be in G.P., then prove that p − q, q − r, r − s are in G.P.

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उत्तर

\[\text { Here, } a_p = a + \left( p - 1 \right)d\]

\[ a_q = a + \left( q - 1 \right)d\]

\[ a_r = a + \left( r - 1 \right)d\]

\[ a_s = a + \left( s - 1 \right)d\]

\[\text { It is given that }a_p , a_q , a_r \text { and } a_s\text {  are in G . P } . \]

\[ \therefore \frac{a_q}{a_p} = \frac{a_r}{a_q} = \frac{a_q - a_r}{a_p - a_q} = \frac{q - r}{p - q} . . . . . . . (i)\]

\[\text { Similarly }, \frac{a_r}{a_q} = \frac{a_s}{a_r} = \frac{a_r - a_s}{a_q - a_r} = \frac{r - s}{q - r} . . . . . . . (ii)\]

\[\text { Using  }\left( i \right) \text { and  }\left( ii \right): \]

\[\frac{q - r}{p - q} = \frac{r - s}{q - r}, \]

\[\text { Therefore }, p - q, q - r\text {  and } r - s \text { are in G . P } .\]

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अध्याय 20: Geometric Progression - Exercise 20.5 [पृष्ठ ४६]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 20 Geometric Progression
Exercise 20.5 | Q 16 | पृष्ठ ४६

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