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Find the sum of the following geometric series: a1+i+a(1+i)2+a(1+i)3+...+a(1+i)n. - Mathematics

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प्रश्न

Find the sum of the following geometric series:

\[\frac{a}{1 + i} + \frac{a}{(1 + i )^2} + \frac{a}{(1 + i )^3} + . . . + \frac{a}{(1 + i )^n} .\]

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उत्तर

`a/(1 + i) + a/(1 + i)^2 + a/(1 + i)^3 + ...... + a/(1 + i)^n`

∴ First term, A = `a/(1 + i)`, No. of terms = n,

Common ratio, R = `(a/(1 + i)^2)/(a/(1 + i))`

R = `(cancel(a)/cancel((1 + i))^2)/(cancel(a)/cancel(1 + i))`

∴ R = `1/(1 + i)`

`"S"_"n" = "A" [(1 - "R"^n)/(1 - "R")]`

`= a/(1 + i) [(1 - (1/(1 + i))^n)/(1 - 1/(1 + i))]`

`= a/cancel(1 + i) [(1 - 1/(1 + i)^n)/((cancel(1)  +  i  - cancel(1))/cancel(1 + i))]`

`= a/i xx i/i [1 - (1 + i)^-n]`

`= (ai)/i^2 [1 - (1 + i)^-n]`

`= (ai)/-1 [1 - (1 + i)^-n]`

= - ai [1 - (1 + i)-n]

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अध्याय 20: Geometric Progression - Exercise 20.3 [पृष्ठ २७]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 20 Geometric Progression
Exercise 20.3 | Q 2.6 | पृष्ठ २७

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