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For the G.P. if r = − 3 and t6 = 1701, find a.

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प्रश्न

For the G.P. if r = − 3 and t6 = 1701, find a.

योग
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उत्तर

tn = arn−1, where r = − 3

∴ t6 = a(−3)6 −1 = 1701

∴ a(− 3)5 = 1701

∴ − 243a = 1701

∴ a = `(1701)/(-243)`

= − 7

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अध्याय 2: Sequences and Series - Exercise 2.1 [पृष्ठ २७]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 2 Sequences and Series
Exercise 2.1 | Q 2. (iii) | पृष्ठ २७

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