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If X = (43) (46) (46) (49) .... (43x) = (0.0625)−54, the Value of X is

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प्रश्न

If x = (43) (46) (46) (49) .... (43x) = (0.0625)−54, the value of x is 

विकल्प

  • (a) 7 

  • (b) 8 

  • (c) 9 

  • (d) 10 

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उत्तर

(b) 8 

\[\left( 4^3 \right)\left( 4^6 \right)\left( 4^9 \right)\left( 4^{12} \right) . . . \left( 4^{3x} \right) = \left( 0 . 0625 \right)^{- 54} \]
\[ \Rightarrow 4^\left( 3 + 6 + 9 + 12 + . . . + 3x \right) = \left( \frac{625}{10000} \right)^{- 54} \]
\[ \Rightarrow 4^{3\left( 1 + 2 + 3 + 4 + . . . + x \right)} = \left( \frac{1}{16} \right)^{- 54} \]
\[ \Rightarrow 4^{3\left( \frac{x\left( x + 1 \right)}{2} \right)} = \left( \frac{1}{16} \right)^{- 54} \]
\[ \Rightarrow 4^{3\left( \frac{x\left( x + 1 \right)}{2} \right)} = \left( 4^{- 2} \right)^{- 54} \]
\[\text{ Comparing both the sides }: \]
\[ \Rightarrow 3\left( \frac{x\left( x + 1 \right)}{2} \right) = 108\]
\[ \Rightarrow x\left( x + 1 \right) = 72\]
\[ \Rightarrow x^2 + x - 72 = 0\]
\[ \Rightarrow x^2 + 9x - 8x - 72 = 0\]
\[ \Rightarrow x\left( x + 9 \right) - 8\left( x + 9 \right) = 0\]
\[ \Rightarrow \left( x + 9 \right)\left( x - 8 \right) = 0\]
\[ \Rightarrow x = 8, - 9\]
\[ \Rightarrow x = 8 [ \because \text{ x is positive }]\]

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अध्याय 20: Geometric Progression - Exercise 20.8 [पृष्ठ ५८]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 20 Geometric Progression
Exercise 20.8 | Q 18 | पृष्ठ ५८

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