हिंदी

If A, B, C, D Are in G.P., Prove That: (B + C) (B + D) = (C + A) (C + D)

Advertisements
Advertisements

प्रश्न

If a, b, c, d are in G.P., prove that:

(b + c) (b + d) = (c + a) (c + d)

Advertisements

उत्तर

a, b, c and d are in G.P.

\[\therefore b^2 = ac\]

\[bc = ad\]

\[ c^2 = bd\]             .......(1)

\[\text {  LHS } = \left( b + c \right)\left( b + d \right)\]

\[ = b^2 + bd + bc + cd\]

\[ = ac + c^2 + ad + cd \left[ \text { Using } (1) \right]\]

\[ = c\left( a + c \right) + d\left( a + c \right)\]

\[ = \left( c + a \right)\left( c + d \right) =\text {  RHS }\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the sum to 20 terms in the geometric progression 0.15, 0.015, 0.0015,…


Find four numbers forming a geometric progression in which third term is greater than the first term by 9, and the second term is greater than the 4th by 18.


Show that the ratio of the sum of first n terms of a G.P. to the sum of terms from (n + 1)th to (2n)th term is `1/r^n`.


The sum of some terms of G.P. is 315 whose first term and the common ratio are 5 and 2, respectively. Find the last term and the number of terms.


A G.P. consists of an even number of terms. If the sum of all the terms is 5 times the sum of terms occupying odd places, then find its common ratio.


if `(a+ bx)/(a - bx) = (b +cx)/(b - cx) = (c + dx)/(c- dx) (x != 0)` then show that a, b, c and d are in G.P.


The sum of first three terms of a G.P. is 13/12 and their product is − 1. Find the G.P.


Find the sum of the following geometric progression:

2, 6, 18, ... to 7 terms;


Find the sum of the following geometric series:

\[\frac{2}{9} - \frac{1}{3} + \frac{1}{2} - \frac{3}{4} + . . . \text { to 5 terms };\]


Find the sum of the following series:

0.5 + 0.55 + 0.555 + ... to n terms.


A G.P. consists of an even number of terms. If the sum of all the terms is 5 times the sum of the terms occupying the odd places. Find the common ratio of the G.P.


Find the sum of the following serie to infinity:

\[1 - \frac{1}{3} + \frac{1}{3^2} - \frac{1}{3^3} + \frac{1}{3^4} + . . . \infty\]


Find the sum of the following series to infinity:

`1/3+1/5^2 +1/3^3+1/5^4 + 1/3^5 + 1/56+ ...infty`


Find the sum of the terms of an infinite decreasing G.P. in which all the terms are positive, the first term is 4, and the difference between the third and fifth term is equal to 32/81.


Find the rational numbers having the following decimal expansion: 

\[0 . \overline3\]


The sum of first two terms of an infinite G.P. is 5 and each term is three times the sum of the succeeding terms. Find the G.P.


If a, b, c are in G.P., prove that \[\frac{1}{\log_a m}, \frac{1}{\log_b m}, \frac{1}{\log_c m}\] are in A.P.


If (a − b), (b − c), (c − a) are in G.P., then prove that (a + b + c)2 = 3 (ab + bc + ca)


If \[\frac{1}{a + b}, \frac{1}{2b}, \frac{1}{b + c}\] are three consecutive terms of an A.P., prove that a, b, c are the three consecutive terms of a G.P.


If a, b, c are in A.P., b,c,d are in G.P. and \[\frac{1}{c}, \frac{1}{d}, \frac{1}{e}\] are in A.P., prove that a, c,e are in G.P.


Insert 6 geometric means between 27 and  \[\frac{1}{81}\] .


Insert 5 geometric means between \[\frac{32}{9}\text{and}\frac{81}{2}\] .


If (p + q)th and (p − q)th terms of a G.P. are m and n respectively, then write is pth term.


Write the product of n geometric means between two numbers a and b. 

 


The sum of an infinite G.P. is 4 and the sum of the cubes of its terms is 92. The common ratio of the original G.P. is 


The product (32), (32)1/6 (32)1/36 ... to ∞ is equal to 


The numbers 3, x, and x + 6 form are in G.P. Find x


The numbers 3, x, and x + 6 form are in G.P. Find 20th term.


The numbers 3, x, and x + 6 form are in G.P. Find nth term


The numbers x − 6, 2x and x2 are in G.P. Find x


Find the sum to n terms of the sequence.

0.2, 0.02, 0.002, ...


For a sequence, if Sn = 2(3n –1), find the nth term, hence show that the sequence is a G.P.


Select the correct answer from the given alternative.

If common ratio of the G.P is 5, 5th term is 1875, the first term is -


Select the correct answer from the given alternative.

Sum to infinity of a G.P. 5, `-5/2, 5/4, -5/8, 5/16,...` is –


Answer the following:

For a sequence , if tn = `(5^("n" - 2))/(7^("n" - 3))`, verify whether the sequence is a G.P. If it is a G.P., find its first term and the common ratio.


Answer the following:

Which 2 terms are inserted between 5 and 40 so that the resulting sequence is G.P.


Answer the following:

Find the sum of infinite terms of `1 + 4/5 + 7/25 + 10/125 + 13/6225 + ...`


Let S be the sum, P be the product and R be the sum of the reciprocals of 3 terms of a G.P. Then P2 R3 : S3 is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×