हिंदी

Select the correct answer from the given alternative. Which term of the geometric progression 1, 2, 4, 8, ... is 2048

Advertisements
Advertisements

प्रश्न

Select the correct answer from the given alternative.

Which term of the geometric progression 1, 2, 4, 8, ... is 2048

विकल्प

  • 10th 

  • 11th 

  • 12th 

  • 13th 

MCQ
Advertisements

उत्तर

12th 

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Sequences and Series - Miscellaneous Exercise 2.1 [पृष्ठ ४१]

APPEARS IN

बालभारती Mathematics and Statistics (Arts and Science) Part 2 [English] Standard 11 Maharashtra State Board
अध्याय 2 Sequences and Series
Miscellaneous Exercise 2.1 | Q I. (4) | पृष्ठ ४१

संबंधित प्रश्न

Which term of the following sequence:

`1/3, 1/9, 1/27`, ...., is `1/19683`?


If a and b are the roots of are roots of x2 – 3x + p = 0 , and c, d are roots of x2 – 12x + q = 0, where a, b, c, d, form a G.P. Prove that (q + p): (q – p) = 17 : 15.


Show that one of the following progression is a G.P. Also, find the common ratio in case:

\[a, \frac{3 a^2}{4}, \frac{9 a^3}{16}, . . .\]


Find:
the ninth term of the G.P. 1, 4, 16, 64, ...


Find :

the 8th term of the G.P. 0.3, 0.06, 0.012, ...


Which term of the G.P. :

\[\sqrt{2}, \frac{1}{\sqrt{2}}, \frac{1}{2\sqrt{2}}, \frac{1}{4\sqrt{2}}, . . . \text { is }\frac{1}{512\sqrt{2}}?\]


The fourth term of a G.P. is 27 and the 7th term is 729, find the G.P.


The 4th term of a G.P. is square of its second term, and the first term is − 3. Find its 7th term.


If the pth and qth terms of a G.P. are q and p, respectively, then show that (p + q)th term is \[\left( \frac{q^p}{p^q} \right)^\frac{1}{p - q}\].


Find the sum of the following geometric series:

\[\frac{a}{1 + i} + \frac{a}{(1 + i )^2} + \frac{a}{(1 + i )^3} + . . . + \frac{a}{(1 + i )^n} .\]


Find the sum of the following series:

9 + 99 + 999 + ... to n terms;


The 4th and 7th terms of a G.P. are \[\frac{1}{27} \text { and } \frac{1}{729}\] respectively. Find the sum of n terms of the G.P.


Find the sum :

\[\sum^{10}_{n = 1} \left[ \left( \frac{1}{2} \right)^{n - 1} + \left( \frac{1}{5} \right)^{n + 1} \right] .\]


Find the sum of the following serie to infinity:

8 +  \[4\sqrt{2}\] + 4 + ... ∞


Prove that: (21/4 . 41/8 . 81/16. 161/32 ... ∞) = 2.


If Sp denotes the sum of the series 1 + rp + r2p + ... to ∞ and sp the sum of the series 1 − rp + r2p − ... to ∞, prove that Sp + sp = 2 . S2p.


If a, b, c are in G.P., prove that:

\[\frac{1}{a^2 - b^2} + \frac{1}{b^2} = \frac{1}{b^2 - c^2}\]


If a, b, c, d are in G.P., prove that:

(a2 − b2), (b2 − c2), (c2 − d2) are in G.P.


If \[\frac{1}{a + b}, \frac{1}{2b}, \frac{1}{b + c}\] are three consecutive terms of an A.P., prove that a, b, c are the three consecutive terms of a G.P.


Insert 5 geometric means between \[\frac{32}{9}\text{and}\frac{81}{2}\] .


If A be one A.M. and p, q be two G.M.'s between two numbers, then 2 A is equal to 


Check whether the following sequence is G.P. If so, write tn.

1, –5, 25, –125 …


For what values of x, the terms `4/3`, x, `4/27` are in G.P.?


Find three numbers in G.P. such that their sum is 21 and sum of their squares is 189.


The numbers x − 6, 2x and x2 are in G.P. Find 1st term


For the following G.P.s, find Sn.

p, q, `"q"^2/"p", "q"^3/"p"^2,` ...


For the following G.P.s, find Sn.

`sqrt(5)`, −5, `5sqrt(5)`, −25, ...


If the common ratio of a G.P. is `2/3` and sum to infinity is 12. Find the first term


If the first term of the G.P. is 16 and its sum to infinity is `96/17` find the common ratio.


Insert two numbers between 1 and −27 so that the resulting sequence is a G.P.


If the A.M. of two numbers exceeds their G.M. by 2 and their H.M. by `18/5`, find the numbers.


Select the correct answer from the given alternative.

If common ratio of the G.P is 5, 5th term is 1875, the first term is -


The sum of 3 terms of a G.P. is `21/4` and their product is 1 then the common ratio is ______.


Answer the following:

For a sequence Sn = 4(7n – 1) verify that the sequence is a G.P.


Answer the following:

If a, b, c are in G.P. and ax2 + 2bx + c = 0 and px2 + 2qx + r = 0 have common roots then verify that pb2 – 2qba + ra2 = 0


If a, b, c, d are four distinct positive quantities in G.P., then show that a + d > b + c


If the pth and qth terms of a G.P. are q and p respectively, show that its (p + q)th term is `(q^p/p^q)^(1/(p - q))`


The sum or difference of two G.P.s, is again a G.P.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×