हिंदी

Given a G.P. with a = 729 and 7th term 64, determine S7.

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प्रश्न

Given a G.P. with a = 729 and 7th term 64, determine S7.

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उत्तर

गुणोत्तर श्रेणी का पहला पद, a = 729

मान लीजिए सार्व अनुपात = r

∴ 7वाँ पद = ar7-1 = ar6

729 r6 = 64

⇒ r6 = `64/729 = (2/3)^6`

∴ r = `2/3`

अब S7 = `("a"(1 - "r"^"n"))/(1 - "r")`

= `(729[1 - (2/3)^7])/(1 - 2/3)`

= `729 xx 3 xx [(2187 - 128)/2187]`

= `(729 xx 3)/2187 (2059)`

= 2059

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अध्याय 8: Sequences and Series - EXERCISE 8.2 [पृष्ठ १४५]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 8 Sequences and Series
EXERCISE 8.2 | Q 15. | पृष्ठ १४५

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