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Given a G.P. with a = 729 and 7th term 64, determine S7. - Mathematics

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Question

Given a G.P. with a = 729 and 7th term 64, determine S7.

Sum
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Solution

गुणोत्तर श्रेणी का पहला पद, a = 729

मान लीजिए सार्व अनुपात = r

∴ 7वाँ पद = ar7-1 = ar6

729 r6 = 64

⇒ r6 = `64/729 = (2/3)^6`

∴ r = `2/3`

अब S7 = `("a"(1 - "r"^"n"))/(1 - "r")`

= `(729[1 - (2/3)^7])/(1 - 2/3)`

= `729 xx 3 xx [(2187 - 128)/2187]`

= `(729 xx 3)/2187 (2059)`

= 2059

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Chapter 9: Sequences and Series - Exercise 9.3 [Page 192]

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NCERT Mathematics [English] Class 11
Chapter 9 Sequences and Series
Exercise 9.3 | Q 15 | Page 192

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