English

The nth term of a G.P. is 128 and the sum of its n terms is 255. If its common ratio is 2, then its first term is ______.

Advertisements
Advertisements

Question

The nth term of a G.P. is 128 and the sum of its n terms is 255. If its common ratio is 2, then its first term is ______.

Options

  • 1

  • none of these 

MCQ
Fill in the Blanks
Advertisements

Solution

The nth term of a G.P. is 128 and the sum of its n terms is 255. If its common ratio is 2, then its first term is 1.

Explanation:

Tn = arn-1 = 128     ...(1)

`S_n = (a(r^n-1))/(r-1)`    ...(2)

`=> (128r-a)/(r-1) = 255`

Put r = 2 

a = 1

shaalaa.com
  Is there an error in this question or solution?

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Find a G.P. for which sum of the first two terms is –4 and the fifth term is 4 times the third term.


Insert two numbers between 3 and 81 so that the resulting sequence is G.P.


The sum of some terms of G.P. is 315 whose first term and the common ratio are 5 and 2, respectively. Find the last term and the number of terms.


The first term of a G.P. is 1. The sum of the third term and fifth term is 90. Find the common ratio of G.P.


Show that one of the following progression is a G.P. Also, find the common ratio in case:

4, −2, 1, −1/2, ...


Find : 

nth term of the G.P.

\[\sqrt{3}, \frac{1}{\sqrt{3}}, \frac{1}{3\sqrt{3}}, . . .\]


In a GP the 3rd term is 24 and the 6th term is 192. Find the 10th term.


The sum of first three terms of a G.P. is 13/12 and their product is − 1. Find the G.P.


Find the sum of the following geometric progression:

4, 2, 1, 1/2 ... to 10 terms.


Find the sum of the following geometric series:

\[\frac{2}{9} - \frac{1}{3} + \frac{1}{2} - \frac{3}{4} + . . . \text { to 5 terms };\]


Find the sum of the following geometric series:

1, −a, a2, −a3, ....to n terms (a ≠ 1)


Evaluate the following:

\[\sum^{10}_{n = 2} 4^n\]


A G.P. consists of an even number of terms. If the sum of all the terms is 5 times the sum of the terms occupying the odd places. Find the common ratio of the G.P.


Find the sum of the following series to infinity:

10 − 9 + 8.1 − 7.29 + ... ∞


Prove that: (91/3 . 91/9 . 91/27 ... ∞) = 3.


If Sp denotes the sum of the series 1 + rp + r2p + ... to ∞ and sp the sum of the series 1 − rp + r2p − ... to ∞, prove that Sp + sp = 2 . S2p.


If a, b, c are in G.P., prove that:

\[a^2 b^2 c^2 \left( \frac{1}{a^3} + \frac{1}{b^3} + \frac{1}{c^3} \right) = a^3 + b^3 + c^3\]


If a, b, c are in G.P., prove that the following is also in G.P.:

a3, b3, c3


If pth, qth, rth and sth terms of an A.P. be in G.P., then prove that p − q, q − r, r − s are in G.P.


If \[\frac{1}{a + b}, \frac{1}{2b}, \frac{1}{b + c}\] are three consecutive terms of an A.P., prove that a, b, c are the three consecutive terms of a G.P.


If S be the sum, P the product and R be the sum of the reciprocals of n terms of a GP, then P2 is equal to


The sum of an infinite G.P. is 4 and the sum of the cubes of its terms is 92. The common ratio of the original G.P. is 


Given that x > 0, the sum \[\sum^\infty_{n = 1} \left( \frac{x}{x + 1} \right)^{n - 1}\] equals 


For the following G.P.s, find Sn

3, 6, 12, 24, ...


For a G.P. if S5 = 1023 , r = 4, Find a


For a G.P. if a = 2, r = 3, Sn = 242 find n


If the first term of the G.P. is 16 and its sum to infinity is `96/17` find the common ratio.


The midpoints of the sides of a square of side 1 are joined to form a new square. This procedure is repeated indefinitely. Find the sum of the areas of all the squares


Answer the following:

Find five numbers in G.P. such that their product is 243 and sum of second and fourth number is 10.


Answer the following:

Find the sum of infinite terms of `1 + 4/5 + 7/25 + 10/125 + 13/6225 + ...`


At the end of each year the value of a certain machine has depreciated by 20% of its value at the beginning of that year. If its initial value was Rs 1250, find the value at the end of 5 years.


If a, b, c, d are four distinct positive quantities in G.P., then show that a + d > b + c


The lengths of three unequal edges of a rectangular solid block are in G.P. The volume of the block is 216 cm3 and the total surface area is 252cm2. The length of the longest edge is ______.


For a, b, c to be in G.P. the value of `(a - b)/(b - c)` is equal to ______.


The sum of the first three terms of a G.P. is S and their product is 27. Then all such S lie in ______.


Let A1, A2, A3, .... be an increasing geometric progression of positive real numbers. If A1A3A5A7 = `1/1296` and A2 + A4 = `7/36`, then the value of A6 + A8 + A10 is equal to ______. 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×