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Which term of the G.P. 5, 25, 125, 625, … is 510?

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Question

Which term of the G.P. 5, 25, 125, 625, … is 510?

Sum
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Solution

Let nth term, i.e., tn be 510.

∴ tn = 510

∴ arn–1 = `1/(5^10)`, where a = 5, r = 5

∴ 5.(5)n–1 = 510

∴ 5n = 510

∴ n = 10

Hence, t10 of the G.P. is 510.

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Chapter 2: Sequences and Series - Exercise 2.1 [Page 27]

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