English

In a G.P. If the (M + N)Th Term is P and (M − N)Th Term is Q, Then Its Mth Term is

Advertisements
Advertisements

Question

In a G.P. if the (m + n)th term is p and (m − n)th term is q, then its mth term is 

Options

  • (a) 0 

  • (b) pq

  • (c) \[\sqrt{pq}\]

  • (d) \[\frac{1}{2}(p + q)\] 

MCQ
Advertisements

Solution

(c) \[\sqrt{pq}\] 

\[\text{ Here }, a_\left( m + n \right) = p\]
\[ \Rightarrow a r^\left( m + n - 1 \right) = p . . . . . . . (i)\]
\[\text{ Also }, a_\left( m - n \right) = q\]
\[ \Rightarrow a r^\left( m - n - 1 \right) = q . . . . . . . (ii)\]
\[\text{ Mutliplying } (i) \text{ and } (ii): \]
\[ \Rightarrow a r^\left( m + n - 1 \right) a r^\left( m - n - 1 \right) = pq\]
\[ \Rightarrow a^2 r^\left( 2m - 2 \right) = pq\]
\[ \Rightarrow \left( a r^\left( m - 1 \right) \right)^2 = pq\]
\[ \Rightarrow a r^\left( m - 1 \right) = \sqrt{pq}\]
\[ \Rightarrow a_m = \sqrt{pq}\]
\[\text{ Thus, the } m^{th} \text{ term is }  \sqrt{pq} . \]

shaalaa.com
  Is there an error in this question or solution?
Chapter 20: Geometric Progression - Exercise 20.8 [Page 58]

APPEARS IN

R.D. Sharma Mathematics [English] Class 11
Chapter 20 Geometric Progression
Exercise 20.8 | Q 24 | Page 58

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Find the 20th and nthterms of the G.P. `5/2, 5/4 , 5/8,...`


How many terms of G.P. 3, 32, 33, … are needed to give the sum 120?


Find the sum of the products of the corresponding terms of the sequences `2, 4, 8, 16, 32 and 128, 32, 8, 2, 1/2`


The sum of two numbers is 6 times their geometric mean, show that numbers are in the ratio `(3 + 2sqrt2) ":" (3 - 2sqrt2)`.


A G.P. consists of an even number of terms. If the sum of all the terms is 5 times the sum of terms occupying odd places, then find its common ratio.


Find :

the 8th term of the G.P. 0.3, 0.06, 0.012, ...


Find : 

nth term of the G.P.

\[\sqrt{3}, \frac{1}{\sqrt{3}}, \frac{1}{3\sqrt{3}}, . . .\]


Which term of the G.P. :

\[2, 2\sqrt{2}, 4, . . .\text {  is }128 ?\]


In a GP the 3rd term is 24 and the 6th term is 192. Find the 10th term.


The product of three numbers in G.P. is 216. If 2, 8, 6 be added to them, the results are in A.P. Find the numbers.


Find the sum of the following geometric progression:

1, −1/2, 1/4, −1/8, ... to 9 terms;


Find the sum of the following geometric series:

\[\sqrt{2} + \frac{1}{\sqrt{2}} + \frac{1}{2\sqrt{2}} + . . .\text { to 8  terms };\]


Find the sum of the following geometric series:

(x +y) + (x2 + xy + y2) + (x3 + x2y + xy2 + y3) + ... to n terms;


Find the sum of the following geometric series:

\[\frac{a}{1 + i} + \frac{a}{(1 + i )^2} + \frac{a}{(1 + i )^3} + . . . + \frac{a}{(1 + i )^n} .\]


Find the sum of the following geometric series:

1, −a, a2, −a3, ....to n terms (a ≠ 1)


How many terms of the series 2 + 6 + 18 + ... must be taken to make the sum equal to 728?


Find the rational numbers having the following decimal expansion: 

\[0 . \overline3\]


Find the rational numbers having the following decimal expansion: 

\[0 . 6\overline8\]


If a, b, c are in G.P., prove that the following is also in G.P.:

a2, b2, c2


If (a − b), (b − c), (c − a) are in G.P., then prove that (a + b + c)2 = 3 (ab + bc + ca)


If xa = xb/2 zb/2 = zc, then prove that \[\frac{1}{a}, \frac{1}{b}, \frac{1}{c}\] are in A.P.

  

Find the geometric means of the following pairs of number:

2 and 8


Find the geometric means of the following pairs of number:

a3b and ab3


If the sum of an infinite decreasing G.P. is 3 and the sum of the squares of its term is \[\frac{9}{2}\], then write its first term and common difference.


Check whether the following sequence is G.P. If so, write tn.

`sqrt(5), 1/sqrt(5), 1/(5sqrt(5)), 1/(25sqrt(5))`, ...


Check whether the following sequence is G.P. If so, write tn.

7, 14, 21, 28, …


The numbers x − 6, 2x and x2 are in G.P. Find 1st term


For a G.P. a = 2, r = `-2/3`, find S6


For a G.P. If t3 = 20 , t6 = 160 , find S7


Find: `sum_("r" = 1)^10 5 xx 3^"r"`


Determine whether the sum to infinity of the following G.P.s exist, if exists find them:

`-3, 1, (-1)/3, 1/9, ...`


If the common ratio of a G.P. is `2/3` and sum to infinity is 12. Find the first term


If the first term of the G.P. is 16 and its sum to infinity is `96/17` find the common ratio.


Find `sum_("r" = 0)^oo (-8)(-1/2)^"r"` 


The sum of 3 terms of a G.P. is `21/4` and their product is 1 then the common ratio is ______.


In a G.P. of even number of terms, the sum of all terms is 5 times the sum of the odd terms. The common ratio of the G.P. is ______.


The third term of a G.P. is 4, the product of the first five terms is ______.


For an increasing G.P. a1, a2 , a3 ........., an, if a6 = 4a4, a9 – a7 = 192, then the value of `sum_(i = 1)^∞ 1/a_i` is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×