English

If P, Q Be Two A.M.'S and G Be One G.M. Between Two Numbers, Then G2 =

Advertisements
Advertisements

Question

If pq be two A.M.'s and G be one G.M. between two numbers, then G2

Options

  • (a) (2p − q) (p −  2q)

  • (b) (2p − q) (2q − p)

  • (c) (2p − q) (p + 2q)

  • (d) none of these

MCQ
Advertisements

Solution

(a) (2p − q) (p − 2q

\[\text{ Let the two numbers be a and b } . \]
\[\text{ a, p, q and b are in A . P } . \]
\[ \therefore p - a = q - p = b - q \]
\[ \Rightarrow p - a = q - p \text{ and } q - p = b - q\]
\[ \Rightarrow a = 2p - q \text{ and } b = 2q - p (i)\]
\[\text{ Also, a, G and b are in G . P }. \]
\[ \therefore G^2 = ab\]
\[ \Rightarrow G^2 = \left( 2p - q \right)\left( 2q - p \right)\] 

shaalaa.com
  Is there an error in this question or solution?
Chapter 20: Geometric Progression - Exercise 20.8 [Page 58]

APPEARS IN

R.D. Sharma Mathematics [English] Class 11
Chapter 20 Geometric Progression
Exercise 20.8 | Q 16 | Page 58

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Which term of the following sequence:

`sqrt3, 3, 3sqrt3`, .... is 729?


Find the sum of the products of the corresponding terms of the sequences `2, 4, 8, 16, 32 and 128, 32, 8, 2, 1/2`


If the pth, qth and rth terms of a G.P. are a, b and c, respectively. Prove that `a^(q - r) b^(r-p) c^(p-q) = 1`.


The sum of some terms of G.P. is 315 whose first term and the common ratio are 5 and 2, respectively. Find the last term and the number of terms.


The first term of a G.P. is 1. The sum of the third term and fifth term is 90. Find the common ratio of G.P.


Let S be the sum, P the product and R the sum of reciprocals of n terms in a G.P. Prove that P2Rn = Sn


Show that one of the following progression is a G.P. Also, find the common ratio in case:

4, −2, 1, −1/2, ...


Find :

the 8th term of the G.P. 0.3, 0.06, 0.012, ...


Which term of the G.P.: `sqrt3, 3, 3sqrt3`, ... is 729?


In a GP the 3rd term is 24 and the 6th term is 192. Find the 10th term.


The sum of first three terms of a G.P. is \[\frac{39}{10}\] and their product is 1. Find the common ratio and the terms.

 

The sum of three numbers in G.P. is 14. If the first two terms are each increased by 1 and the third term decreased by 1, the resulting numbers are in A.P. Find the numbers.


Find the sum of the following geometric progression:

(a2 − b2), (a − b), \[\left( \frac{a - b}{a + b} \right)\] to n terms;


Find the sum of the following geometric series:

\[\frac{2}{9} - \frac{1}{3} + \frac{1}{2} - \frac{3}{4} + . . . \text { to 5 terms };\]


Find the sum of the following geometric series:

`3/5 + 4/5^2 + 3/5^3 + 4/5^4 + ....` to 2n terms;


Evaluate the following:

\[\sum^{10}_{n = 2} 4^n\]


Find the sum of the following series:

0.5 + 0.55 + 0.555 + ... to n terms.


Find the sum of the terms of an infinite decreasing G.P. in which all the terms are positive, the first term is 4, and the difference between the third and fifth term is equal to 32/81.


Find the rational numbers having the following decimal expansion: 

\[0 .\overline {231 }\]


If a, b, c are in G.P., prove that \[\frac{1}{\log_a m}, \frac{1}{\log_b m}, \frac{1}{\log_c m}\] are in A.P.


If a, b, c, d are in G.P., prove that:

\[\frac{ab - cd}{b^2 - c^2} = \frac{a + c}{b}\]


If pth, qth, rth and sth terms of an A.P. be in G.P., then prove that p − q, q − r, r − s are in G.P.


If \[\frac{1}{a + b}, \frac{1}{2b}, \frac{1}{b + c}\] are three consecutive terms of an A.P., prove that a, b, c are the three consecutive terms of a G.P.


If a, b, c are in A.P., b,c,d are in G.P. and \[\frac{1}{c}, \frac{1}{d}, \frac{1}{e}\] are in A.P., prove that a, c,e are in G.P.


Check whether the following sequence is G.P. If so, write tn.

3, 4, 5, 6, …


Find three numbers in G.P. such that their sum is 21 and sum of their squares is 189.


For the following G.P.s, find Sn.

p, q, `"q"^2/"p", "q"^3/"p"^2,` ...


Find : `sum_("r" = 1)^oo 4(0.5)^"r"`


Find GM of two positive numbers whose A.M. and H.M. are 75 and 48


Insert two numbers between 1 and −27 so that the resulting sequence is a G.P.


Select the correct answer from the given alternative.

Sum to infinity of a G.P. 5, `-5/2, 5/4, -5/8, 5/16,...` is –


Answer the following:

In a G.P., the fourth term is 48 and the eighth term is 768. Find the tenth term


Answer the following:

For a G.P. a = `4/3` and t7 = `243/1024`, find the value of r


Answer the following:

Find `sum_("r" = 1)^"n" (2/3)^"r"`


Answer the following:

If for a G.P. first term is (27)2 and seventh term is (8)2, find S8 


For a, b, c to be in G.P. the value of `(a - b)/(b - c)` is equal to ______.


If in a geometric progression {an}, a1 = 3, an = 96 and Sn = 189, then the value of n is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×