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For a G.P. a = 2, r = -23, find S6

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Question

For a G.P. a = 2, r = `-2/3`, find S6

Sum
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Solution

a = 2, r = `-2/3`

Sn = `("a"(1 - "r"^"n"))/(1 - "r")`, for r < 1

S6 = `(2[1 - (-2/3)^6])/(1 - (-2/3)`

= `(2[1 - (2/3)^6])/(5/3)`

= `6/5[(729 - 64)/3^6]`

= `6/5[665/729]`

S6 = `266/243`

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Chapter 2: Sequences and Series - Exercise 2.2 [Page 31]

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