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Which term of the following sequence: 3,3,33, .... is 729? - Mathematics

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Question

Which term of the following sequence:

`sqrt3, 3, 3sqrt3`, .... is 729?

Sum
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Solution

The given sequence is `sqrt3, 3, 3sqrt3`,...

Here, a = `sqrt3` and r = `3/sqrt3 = 3`

Let the nth term of the given sequence be 729.

an = arn- 1

∴ arn - 1 = 729

= `(sqrt3)(sqrt3)^("n" - 1)` = 729

= `(3)^(1/2) (3)^((n - 1)/2) = (3)^6`

= `(3)^(1/2 + (n - 1)/2) =  (3)^6`

∴ `1/2 + (n - 1)/2 = 6`

= `(1 + n - 1)/2 = 6`

= n = 12

Thus, the 12th term of the given sequence is 729.

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Chapter 9: Sequences and Series - Exercise 9.3 [Page 192]

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NCERT Mathematics [English] Class 11
Chapter 9 Sequences and Series
Exercise 9.3 | Q 5.2 | Page 192

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