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The Common Ratio of a G.P. is 3 and the Last Term is 486. If the Sum of These Terms Be 728, Find the First Term.

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Question

The common ratio of a G.P. is 3 and the last term is 486. If the sum of these terms be 728, find the first term.

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Solution

Here, common ratio, = 3
nth term, an = 486
Sn = 728

\[a_n = 486 \]

\[ \Rightarrow a r^{n - 1} = 486\]

\[ \Rightarrow a \left( 3 \right)^{n - 1} = 486 \]

\[ \Rightarrow a \left( 3 \right)^n = 486 \times 3 \]

\[ \Rightarrow a \left( 3 \right)^n = 1458 . . . \left( i \right)\]

\[\text { Now, } S_n = 728\]

\[ \Rightarrow 728 = a \left( \frac{3^n - 1}{3 - 1} \right) \]

\[ \Rightarrow 728 = \left\{ \frac{a \left( 3 \right)^n - a}{2} \right\}\]

\[ \Rightarrow 1456 = a \left( 3 \right)^{n - 1} - a \]

\[ \Rightarrow 1456 = 1458 - a \left[ \text { From } \left( i \right) \right]\]

\[ \Rightarrow a = 1458 - 1456 \]

\[ \Rightarrow a = 2\]

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Chapter 20: Geometric Progression - Exercise 20.3 [Page 28]

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R.D. Sharma Mathematics [English] Class 11
Chapter 20 Geometric Progression
Exercise 20.3 | Q 9 | Page 28

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