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If a, b, c, d are in G.P., prove that a2 – b2, b2 – c2, c2 – d2 are also in G.P.

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Question

If a, b, c, d are in G.P., prove that a2 – b2, b2 – c2, c2 – d2 are also in G.P.

Sum
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Solution

Let r be the common ratio of the given G.P.

Then `b/a = c/b = d/c` = r

⇒ b = ar, c = br = ar2, d = cr = ar3

Now, a2 – b2 = a2 – a2r2

= a2(1 – r2)

b2 – c2 = a2r2 – a2r4

= a2r2 (1 – r2)

And c2 – d2 = a2r4 – a2r6

= a2r4(1 – r2)

Therefore, `(b^2 - c^2)/(a^2 - b^2) = (c^2 - d^2)/(b^2 - c^2)` = r2

Hence, a2 – b2, b2 – c2, c2 – d2 are in G.P.

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Chapter 9: Sequences and Series - Solved Examples [Page 153]

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NCERT Exemplar Mathematics Exemplar [English] Class 11
Chapter 9 Sequences and Series
Solved Examples | Q 8 | Page 153

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