English

Show that the products of the corresponding terms of the sequences a, ar, ar2, …arn – 1 and A, AR, AR2, … ARn-1 form a G.P, and find the common ratio - Mathematics

Advertisements
Advertisements

Question

Show that the products of the corresponding terms of the sequences a, ar, ar2, …arn – 1 and A, AR, AR2, … `AR^(n-1)` form a G.P, and find the common ratio

Sum
Advertisements

Solution

% Sequence a, ar, ar2, …. The sequence formed by the product of arn – 1 and the corresponding terms of A, AR, AR2, .... ARn – 1

`("Second term")/("First term")` = `(arAR)/(aA) = rR`

`("Third term")/("Second term")` = `(ar^2 AR^2)/(arAR) = rR`

Thus, the above sequence forms a G.P. and the common ratio is rR.

shaalaa.com
  Is there an error in this question or solution?
Chapter 9: Sequences and Series - Exercise 9.3 [Page 193]

APPEARS IN

NCERT Mathematics [English] Class 11
Chapter 9 Sequences and Series
Exercise 9.3 | Q 20 | Page 193

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

If the 4th, 10th and 16th terms of a G.P. are x, y and z, respectively. Prove that x, y, z are in G.P.


Show that the ratio of the sum of first n terms of a G.P. to the sum of terms from (n + 1)th to (2n)th term is `1/r^n`.


The sum of two numbers is 6 times their geometric mean, show that numbers are in the ratio `(3 + 2sqrt2) ":" (3 - 2sqrt2)`.


if `(a+ bx)/(a - bx) = (b +cx)/(b - cx) = (c + dx)/(c- dx) (x != 0)` then show that a, b, c and d are in G.P.


Find :

the 8th term of the G.P. 0.3, 0.06, 0.012, ...


Find :

the 10th term of the G.P.

\[\sqrt{2}, \frac{1}{\sqrt{2}}, \frac{1}{2\sqrt{2}}, . . .\]


Which term of the progression 0.004, 0.02, 0.1, ... is 12.5?


Find the sum of the following geometric series:

 0.15 + 0.015 + 0.0015 + ... to 8 terms;


Find the sum of the following geometric series:

1, −a, a2, −a3, ....to n terms (a ≠ 1)


Evaluate the following:

\[\sum^n_{k = 1} ( 2^k + 3^{k - 1} )\]


Evaluate the following:

\[\sum^{10}_{n = 2} 4^n\]


Find the sum of the following series:

0.6 + 0.66 + 0.666 + .... to n terms


Let an be the nth term of the G.P. of positive numbers.

Let \[\sum^{100}_{n = 1} a_{2n} = \alpha \text { and } \sum^{100}_{n = 1} a_{2n - 1} = \beta,\] such that α ≠ β. Prove that the common ratio of the G.P. is α/β.


Find the sum of the following series to infinity:

`1/3+1/5^2 +1/3^3+1/5^4 + 1/3^5 + 1/56+ ...infty`


Find the rational numbers having the following decimal expansion: 

\[0 . \overline3\]


Find k such that k + 9, k − 6 and 4 form three consecutive terms of a G.P.


If a, b, c are in G.P., prove that:

a (b2 + c2) = c (a2 + b2)


If a, b, c are in G.P., prove that:

\[\frac{(a + b + c )^2}{a^2 + b^2 + c^2} = \frac{a + b + c}{a - b + c}\]


If a, b, c, d are in G.P., prove that:

(b + c) (b + d) = (c + a) (c + d)


If a, b, c are in G.P., prove that the following is also in G.P.:

a2 + b2, ab + bc, b2 + c2


If a, b, c, d are in G.P., prove that:

(a2 + b2 + c2), (ab + bc + cd), (b2 + c2 + d2) are in G.P.


If A1, A2 be two AM's and G1G2 be two GM's between and b, then find the value of \[\frac{A_1 + A_2}{G_1 G_2}\]


If in an infinite G.P., first term is equal to 10 times the sum of all successive terms, then its common ratio is 


The sum of an infinite G.P. is 4 and the sum of the cubes of its terms is 92. The common ratio of the original G.P. is 


If abc are in G.P. and xy are AM's between ab and b,c respectively, then 


If x = (43) (46) (46) (49) .... (43x) = (0.0625)−54, the value of x is 


Given that x > 0, the sum \[\sum^\infty_{n = 1} \left( \frac{x}{x + 1} \right)^{n - 1}\] equals 


Which term of the G.P. 5, 25, 125, 625, … is 510?


The numbers x − 6, 2x and x2 are in G.P. Find nth term


For the following G.P.s, find Sn

3, 6, 12, 24, ...


Find: `sum_("r" = 1)^10(3 xx 2^"r")`


Express the following recurring decimal as a rational number:

`2.bar(4)`


If the A.M. of two numbers exceeds their G.M. by 2 and their H.M. by `18/5`, find the numbers.


Answer the following:

For a sequence , if tn = `(5^("n" - 2))/(7^("n" - 3))`, verify whether the sequence is a G.P. If it is a G.P., find its first term and the common ratio.


Answer the following:

If for a G.P. t3 = `1/3`, t6 = `1/81` find r


Answer the following:

If a, b, c are in G.P. and ax2 + 2bx + c = 0 and px2 + 2qx + r = 0 have common roots then verify that pb2 – 2qba + ra2 = 0


Answer the following:

If p, q, r, s are in G.P., show that (p2 + q2 + r2) (q2 + r2 + s2) = (pq + qr + rs)2   


The third term of G.P. is 4. The product of its first 5 terms is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×