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Find the Sum of the Following Geometric Progression: 4, 2, 1, 1/2 ... to 10 Terms. - Mathematics

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Question

Find the sum of the following geometric progression:

4, 2, 1, 1/2 ... to 10 terms.

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Solution

Here,a = 4 and r = \[\frac{1}{2}\]

\[\therefore S_n = a\left( \frac{1 - r^{10}}{1 - r} \right)\]

\[ = 4\left( \frac{1 - \left( \frac{1}{2} \right)^{10}}{1 - \left( \frac{1}{2} \right)} \right)\]

\[ = 4\left( \frac{1 - \left( \frac{1}{1024} \right)}{\frac{1}{2}} \right)\]

\[ = 8\left( 1 - \frac{1}{1024} \right)\]

\[ = \frac{1023}{128}\]

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Chapter 20: Geometric Progression - Exercise 20.3 [Page 27]

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RD Sharma Mathematics [English] Class 11
Chapter 20 Geometric Progression
Exercise 20.3 | Q 1.5 | Page 27

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