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Find the sum of the following geometric series: 1, −a, a2, −a3, ....to n terms (a ≠ 1) - Mathematics

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प्रश्न

Find the sum of the following geometric series:

1, −a, a2, −a3, ....to n terms (a ≠ 1)

योग
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उत्तर

Common Ratio = r = `(-a)/1 = -a`

∴ Sum of GP for n terms = `(a(r^n - 1))/(r - 1)`    ...(i)

⇒ a = 1, r = −a, n = n

∴ Substituting the above values in (1) we get

⇒ `(1((-a)^n - 1))/(-a-1)`

⇒ `(-1((-a)^n - 1))/(a+1)` 

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अध्याय 20: Geometric Progression - Exercise 20.3 [पृष्ठ २७]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 20 Geometric Progression
Exercise 20.3 | Q 2.7 | पृष्ठ २७

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