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If A, B, C Are in A.P., B,C,D Are in G.P. and 1 C , 1 D , 1 E Are in A.P., Prove that A, C,E Are in G.P. - Mathematics

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प्रश्न

If a, b, c are in A.P., b,c,d are in G.P. and \[\frac{1}{c}, \frac{1}{d}, \frac{1}{e}\] are in A.P., prove that a, c,e are in G.P.

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उत्तर

\[\text { a, b and c are in A . P }. \]

\[ \therefore 2b = a + c . . . . . . . (i)\]

\[\text { Also, b, c and d are in G . P } . \]

\[ \therefore c^2 = bd . . . . . . . (ii)\]

\[\text {And } \frac{1}{c}, \frac{1}{d} \text { and } \frac{1}{e} \text { are in A . P .} \]

\[ \therefore \frac{2}{d} = \frac{1}{c} + \frac{1}{e} \]

\[ \Rightarrow d = \frac{2ce}{c + e} . . . . . . . (iii)\]

\[ \because c^2 = bd \left[ \text { From }(ii) \right] \]

\[ \Rightarrow c^2 = \left( \frac{a + c}{2} \right)\left( \frac{2ce}{c + e} \right) \left[ \text { Using } (i) \text { and } (iii) \right]\]

\[ \Rightarrow c^2 \left( c + e \right) = ce\left( a + c \right)\]

\[ \Rightarrow c^2 + ce = ae + ec\]

\[ \Rightarrow c^2 = ae\]

\[\text { Therefore, a, c and e are also in G . P } . \]

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अध्याय 20: Geometric Progression - Exercise 20.5 [पृष्ठ ४६]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 20 Geometric Progression
Exercise 20.5 | Q 19 | पृष्ठ ४६

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