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Answer the following: For a sequence , if tn = 5n-27n-3, verify whether the sequence is a G.P. If it is a G.P., find its first term and the common ratio.

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प्रश्न

Answer the following:

For a sequence , if tn = `(5^("n" - 2))/(7^("n" - 3))`, verify whether the sequence is a G.P. If it is a G.P., find its first term and the common ratio.

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उत्तर

tn = `(5^("n" - 2))/(7^("n" - 3)) = (5.5^("n" - 3))/(7^("n" - 3))`

∴ tn = `5(5/7)^("n" - 3)`

∴ tn+1 = `5(5/7)^("n" + 1 - 3)`

= `5(5/7)^("n" - 2)`

∴ `("t"_("n" + 1))/"t"_"n" = (5(5/7)^("n" - 2))/(5(5/7)^("n" - 3))`

= `(5/7)^("n" - 2 - "n" + 3)`

= `5/7`, which is a constant

∴  the sequence is a G.P. whose common ratio is `5/7`

Now, tn = `5(5/7)^("n" - 3)`

∴ the first term = t1 = `5(5/7)^(1 - 3)`

= `5(5/7)^(-2)`

= `5(7/5)^2`

= `49/5`

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Sequences and Series - Miscellaneous Exercise 2.2 [पृष्ठ ४१]

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बालभारती Mathematics and Statistics (Arts and Science) Part 2 [English] Standard 11 Maharashtra State Board
अध्याय 2 Sequences and Series
Miscellaneous Exercise 2.2 | Q II. (4) | पृष्ठ ४१

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