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Find: ∑r=1105×3r

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प्रश्न

Find: `sum_("r" = 1)^10 5 xx 3^"r"`

योग
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उत्तर

`sum_("r" = 1)^10 5 xx 3^"r"`

= 5 x 3 + 5 x 32 + 5 x 33 + … + 5 x 310

= 5[3 + 32 + 33 + ... + 310]

Here, 3, 32, 33, ..., 310 are the terms in G.P. with

a = 3, r = 3

`sum_("r" = 1)^10 5 xx 3^"r" = 5*(3[3^10 - 1])/(3 - 1)`

= `15/2(3^10 - 1)`

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अध्याय 2: Sequences and Series - Exercise 2.2 [पृष्ठ ३२]

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बालभारती Mathematics and Statistics (Arts and Science) Part 2 [English] Standard 11 Maharashtra State Board
अध्याय 2 Sequences and Series
Exercise 2.2 | Q 11. (ii) | पृष्ठ ३२

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