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Find: ∑r=110(3×2r) - Mathematics and Statistics

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प्रश्न

Find: `sum_("r" = 1)^10(3 xx 2^"r")`

योग
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उत्तर

`sum_("r" = 1)^10(3 xx 2^"r") = 3 sum_("r"=1)^10 2"r"`

= 3(2 + 22 + 23 + ... + 210)

Here, 2, 22, 23, ..., 210 are in G.P. with a = 2, r = 2

∴ `sum_("r" = 1)^10(3 xx 2^"r") = 3[(2(2^10 - 1))/(2 -1)]` ....... `[because "S"_"n" = ("a"("r"^"n" -1))/("r" -1)]`

= 6(1024 – 1)

= 6(1023) 

= 6138

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Sequences and Series - Exercise 2.2 [पृष्ठ ३२]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 2 Sequences and Series
Exercise 2.2 | Q 11. (i) | पृष्ठ ३२

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