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Find : Nth Term of the G.P. √ 3 , 1 √ 3 , 1 3 √ 3 , . . . - Mathematics

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प्रश्न

Find : 

nth term of the G.P.

\[\sqrt{3}, \frac{1}{\sqrt{3}}, \frac{1}{3\sqrt{3}}, . . .\]

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उत्तर

Here,

\[\text { First term, } a = \sqrt{3}\]

\[\text { Common ratio, } r = \frac{a_2}{a_1} = \frac{\frac{1}{\sqrt{3}}}{\sqrt{3}} = \frac{1}{3}\]

\[ \therefore \text { nth term } = a_n = a r^{(n - 1)} = \sqrt{3} \left( \frac{1}{3} \right)^{n - 1} \]

\[\text { Thus, the nth term of the given GP is } \sqrt{3} \left( \frac{1}{3} \right)^{n - 1} .\]

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अध्याय 20: Geometric Progression - Exercise 20.1 [पृष्ठ १०]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 20 Geometric Progression
Exercise 20.1 | Q 3.5 | पृष्ठ १०

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