हिंदी

If the first term of the G.P. is 16 and its sum to infinity is 96/17 find the common ratio.

Advertisements
Advertisements

प्रश्न

If the first term of the G.P. is 16 and its sum to infinity is `96/17` find the common ratio.

योग
Advertisements

उत्तर

Given:

First term, a = 16

Sum to infinity, S∞ = `96/17`

Formula for sum to infinity of a G.P.:

`S_∞ = a/(1-r)`, where ∣r∣ < 1

`96/17 = 16/(1-r)`

96(1 − r) = 17 × 16

96 − 96r = 272

−96r = 272 − 96

−96r = 176

`r = -176/96`

`= -11/6`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Sequences and Series - Exercise 2.3 [पृष्ठ ३३]

APPEARS IN

बालभारती Mathematics and Statistics (Arts and Science) Part 2 [English] Standard 11 Maharashtra State Board
अध्याय 2 Sequences and Series
Exercise 2.3 | Q 4 | पृष्ठ ३३

संबंधित प्रश्न

Which term of the following sequence:

`sqrt3, 3, 3sqrt3`, .... is 729?


For what values of x, the numbers  `-2/7, x, -7/2` are in G.P?


How many terms of G.P. 3, 32, 33, … are needed to give the sum 120?


Find a G.P. for which sum of the first two terms is –4 and the fifth term is 4 times the third term.


If a, b, c, d are in G.P, prove that (an + bn), (bn + cn), (cn + dn) are in G.P.


Show that one of the following progression is a G.P. Also, find the common ratio in case:

\[a, \frac{3 a^2}{4}, \frac{9 a^3}{16}, . . .\]


Show that the sequence <an>, defined by an = \[\frac{2}{3^n}\], n ϵ N is a G.P.


Which term of the G.P. :

\[\frac{1}{3}, \frac{1}{9}, \frac{1}{27} . . \text { . is } \frac{1}{19683} ?\]


The 4th term of a G.P. is square of its second term, and the first term is − 3. Find its 7th term.


Find three numbers in G.P. whose product is 729 and the sum of their products in pairs is 819.


Find the sum of the following geometric progression:

1, −1/2, 1/4, −1/8, ... to 9 terms;


Find the sum of the following geometric series:

`sqrt7, sqrt21, 3sqrt7,...` to n terms


Find the sum of the following series:

7 + 77 + 777 + ... to n terms;


Find the sum of the following series:

9 + 99 + 999 + ... to n terms;


If S1, S2, ..., Sn are the sums of n terms of n G.P.'s whose first term is 1 in each and common ratios are 1, 2, 3, ..., n respectively, then prove that S1 + S2 + 2S3 + 3S4 + ... (n − 1) Sn = 1n + 2n + 3n + ... + nn.


Find the sum of the following serie to infinity:

\[1 - \frac{1}{3} + \frac{1}{3^2} - \frac{1}{3^3} + \frac{1}{3^4} + . . . \infty\]


If a, b, c are in G.P., prove that:

a (b2 + c2) = c (a2 + b2)


If a, b, c, d are in G.P., prove that:

\[\frac{1}{a^2 + b^2}, \frac{1}{b^2 - c^2}, \frac{1}{c^2 + d^2} \text { are in G . P } .\]


If (a − b), (b − c), (c − a) are in G.P., then prove that (a + b + c)2 = 3 (ab + bc + ca)


If a, b, c are in A.P. and a, b, d are in G.P., show that a, (a − b), (d − c) are in G.P.


Insert 5 geometric means between 16 and \[\frac{1}{4}\] .


Find the geometric means of the following pairs of number:

a3b and ab3


A ball is dropped from a height of 80 ft. The ball is such that it rebounds `(3/4)^"th"` of the height it has fallen. How high does the ball rebound on 6th bounce? How high does the ball rebound on nth bounce?


The numbers 3, x, and x + 6 form are in G.P. Find 20th term.


The numbers x − 6, 2x and x2 are in G.P. Find nth term


For a G.P. a = 2, r = `-2/3`, find S6


For a G.P. If t4 = 16, t9 = 512, find S10


Find the sum to n terms of the sequence.

0.5, 0.05, 0.005, ...


Determine whether the sum to infinity of the following G.P.s exist, if exists find them:

`-3, 1, (-1)/3, 1/9, ...`


Express the following recurring decimal as a rational number:

`2.bar(4)`


A ball is dropped from a height of 10m. It bounces to a height of 6m, then 3.6m and so on. Find the total distance travelled by the ball


Select the correct answer from the given alternative.

Which term of the geometric progression 1, 2, 4, 8, ... is 2048


Answer the following:

Find three numbers in G.P. such that their sum is 35 and their product is 1000


Answer the following:

For a sequence Sn = 4(7n – 1) verify that the sequence is a G.P.


Answer the following:

Find the sum of infinite terms of `1 + 4/5 + 7/25 + 10/125 + 13/6225 + ...`


If pth, qth, and rth terms of an A.P. and G.P. are both a, b and c respectively, show that ab–c . bc – a . ca – b = 1


For a, b, c to be in G.P. the value of `(a - b)/(b - c)` is equal to ______.


The third term of a G.P. is 4, the product of the first five terms is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×