मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Answer the following: In a G.P., the fourth term is 48 and the eighth term is 768. Find the tenth term - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Answer the following:

In a G.P., the fourth term is 48 and the eighth term is 768. Find the tenth term

बेरीज
Advertisements

उत्तर

Given, t4 = 48, t8 = 768

tn = arn–1

∴ t4 = ar3

∴ ar3 = 48    ...(i)

and ar7 = 768   ...(ii)

Equation (ii) ÷ equation (i), we get

∴ `"ar"^7/"ar"^3 = 768/48`

∴ r4 = 16

∴ r = 2

Substituting r = 2 (i), we get

a.(23) = 48

∴ a = 6

∴ t10 = ar9

∴ t10 = ar9

= 6(29)

= 3072

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Sequences and Series - Miscellaneous Exercise 2.2 [पृष्ठ ४१]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
पाठ 2 Sequences and Series
Miscellaneous Exercise 2.2 | Q II. (1) | पृष्ठ ४१

संबंधित प्रश्‍न

Which term of the following sequence:

`1/3, 1/9, 1/27`, ...., is `1/19683`?


Find the sum to indicated number of terms of the geometric progressions `sqrt7, sqrt21,3sqrt7`...n terms.


If the pth, qth and rth terms of a G.P. are a, b and c, respectively. Prove that `a^(q - r) b^(r-p) c^(p-q) = 1`.


Insert two numbers between 3 and 81 so that the resulting sequence is G.P.


if `(a+ bx)/(a - bx) = (b +cx)/(b - cx) = (c + dx)/(c- dx) (x != 0)` then show that a, b, c and d are in G.P.


Which term of the G.P.: `sqrt3, 3, 3sqrt3`, ... is 729?


The fourth term of a G.P. is 27 and the 7th term is 729, find the G.P.


Find three numbers in G.P. whose sum is 38 and their product is 1728.


Find the sum of the following geometric series:

(x +y) + (x2 + xy + y2) + (x3 + x2y + xy2 + y3) + ... to n terms;


Find the sum of the following geometric series:

1, −a, a2, −a3, ....to n terms (a ≠ 1)


How many terms of the series 2 + 6 + 18 + ... must be taken to make the sum equal to 728?


The sum of n terms of the G.P. 3, 6, 12, ... is 381. Find the value of n.


The 4th and 7th terms of a G.P. are \[\frac{1}{27} \text { and } \frac{1}{729}\] respectively. Find the sum of n terms of the G.P.


Find the sum of the following series to infinity:

10 − 9 + 8.1 − 7.29 + ... ∞


Prove that: (91/3 . 91/9 . 91/27 ... ∞) = 3.


If a, b, c are in G.P., prove that \[\frac{1}{\log_a m}, \frac{1}{\log_b m}, \frac{1}{\log_c m}\] are in A.P.


If a, b, c are in G.P., prove that:

a (b2 + c2) = c (a2 + b2)


If (a − b), (b − c), (c − a) are in G.P., then prove that (a + b + c)2 = 3 (ab + bc + ca)


If the 4th, 10th and 16th terms of a G.P. are x, y and z respectively. Prove that x, y, z are in G.P.


If a, b, c are in A.P., b,c,d are in G.P. and \[\frac{1}{c}, \frac{1}{d}, \frac{1}{e}\] are in A.P., prove that a, c,e are in G.P.


Insert 6 geometric means between 27 and  \[\frac{1}{81}\] .


Insert 5 geometric means between \[\frac{32}{9}\text{and}\frac{81}{2}\] .


If pth, qth and rth terms of a G.P. re x, y, z respectively, then write the value of xq − r yr − pzp − q.

 

 

 


If a = 1 + b + b2 + b3 + ... to ∞, then write b in terms of a.


The value of 91/3 . 91/9 . 91/27 ... upto inf, is 


If second term of a G.P. is 2 and the sum of its infinite terms is 8, then its first term is


The two geometric means between the numbers 1 and 64 are 


Check whether the following sequence is G.P. If so, write tn.

2, 6, 18, 54, …


Check whether the following sequence is G.P. If so, write tn.

1, –5, 25, –125 …


Mosquitoes are growing at a rate of 10% a year. If there were 200 mosquitoes in the beginning. Write down the number of mosquitoes after 3 years.


The numbers x − 6, 2x and x2 are in G.P. Find 1st term


For the following G.P.s, find Sn

3, 6, 12, 24, ...


For a G.P. a = 2, r = `-2/3`, find S6


Find the sum to n terms of the sequence.

0.2, 0.02, 0.002, ...


If S, P, R are the sum, product, and sum of the reciprocals of n terms of a G.P. respectively, then verify that `["S"/"R"]^"n"` = P


The sum of 3 terms of a G.P. is `21/4` and their product is 1 then the common ratio is ______.


Answer the following:

If a, b, c are in G.P. and ax2 + 2bx + c = 0 and px2 + 2qx + r = 0 have common roots then verify that pb2 – 2qba + ra2 = 0


In a G.P. of positive terms, if any term is equal to the sum of the next two terms. Then the common ratio of the G.P. is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×