मराठी

If a+bxa-bx=b+cxb-cx=c+dxc-dx(x≠0) then show that a, b, c and d are in G.P.

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प्रश्न

if `(a+ bx)/(a - bx) = (b +cx)/(b - cx) = (c + dx)/(c- dx) (x != 0)` then show that a, b, c and d are in G.P.

बेरीज
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उत्तर

We know that if `"a"/"b" = "c"/"d"` then `("a" + "b")/("a" - "b") = ("c" + " d")/("c" - "d")`

According to this rule, if `("a" + "bx")/("a" - "bx") = ("b" + "cx")/("b" - "cx") = ("c" + "cx")/("c" - "cx")`

So, `(("a" + "bx") + ("a" - "bx"))/(("a" + "bx") - ("a" - "bx")) = ((" b" + "cx") + ("b" - "cx"))/(("b" + "cx") - ("b" - "cx"))`

= `(("c" + "dx") + ("c" - "dx"))/(("c" + "dx") - ("c" - "dx"))`

`(2"a")/(2"bx") = (2"b")/(2"cx") = (2"c")/(2"dx")`

or `"a"/"b" = "b"/"c" = "c"/"d"`

Hence a, b, c, d are in geometric progression.

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पाठ 8: Sequences and Series - Miscellaneous Exercise [पृष्ठ १४८]

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एनसीईआरटी Mathematics [English] Class 11
पाठ 8 Sequences and Series
Miscellaneous Exercise | Q 6. | पृष्ठ १४८

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