मराठी

Which term of the following sequence: 13,19,127, ...., is 119683?

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प्रश्न

Which term of the following sequence:

`1/3, 1/9, 1/27`, ...., is `1/19683`?

बेरीज
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उत्तर

First term of the geometric series a = `1/3`

Second term = `1/9`

∴ Common ratio = `1/9 ÷ 1/3`

= `1/9 xx 3`

= `1/3`

nth term = arn-1 

= `1/3 (1/3)^("n" -1)`

= `1/3^"n"`

Given: `1/3^"n"`

= `1/19683`

= `1/3^9`

Hence n = 9

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पाठ 8: Sequences and Series - EXERCISE 8.2 [पृष्ठ १४५]

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एनसीईआरटी Mathematics [English] Class 11
पाठ 8 Sequences and Series
EXERCISE 8.2 | Q 5. (c) | पृष्ठ १४५

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