मराठी

If the Sum of First Two Terms of an Infinite Gp is 1 Every Term is Twice the Sum of All the Successive Terms, Then Its First Term is - Mathematics

Advertisements
Advertisements

प्रश्न

If the sum of first two terms of an infinite GP is 1 every term is twice the sum of all the successive terms, then its first term is 

पर्याय

  • (a) 1/3 

  • (b) 2/3

  • (c) 1/4

  • (d) 3/4

MCQ
Advertisements

उत्तर

(d) 3/4 

\[\text{ Let the terms of the G . P } . be a, a_2 , a_3 , a_4 , a_5 , . . . , \infty . \]
\[\text{ And, let the common ratio be r } . \]
\[\text{ Now }, a + a_2 = 1\]
\[ \therefore a + ar = 1 . . . . . . . . (i)\]
\[\text{ Also }, a = 2\left( a_2 + a_3 + a_4 + a_5 + . . . \infty \right)\]
\[ \Rightarrow a = 2\left( ar + a r^2 + a r^3 + a r^4 + . . . \infty \right)\]
\[ \Rightarrow a = 2\left( \frac{ar}{1 - r} \right)\]
\[ \Rightarrow 1 - r = 2r\]
\[ \Rightarrow 3r = 1\]
\[ \Rightarrow r = \frac{1}{3}\]
\[\text{ Putting the value of r in } (i): \]
\[a + \frac{a}{3} = 1\]
\[ \Rightarrow \frac{4a}{3} = 1\]
\[ \Rightarrow 4a = 3\]
\[ \Rightarrow a = \frac{3}{4}\]
\[\]

 

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 20: Geometric Progression - Exercise 20.8 [पृष्ठ ५७]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 11
पाठ 20 Geometric Progression
Exercise 20.8 | Q 11 | पृष्ठ ५७

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

The 4th term of a G.P. is square of its second term, and the first term is –3. Determine its 7thterm.


Find the sum to indicated number of terms in the geometric progressions x3, x5, x7, ... n terms (if x ≠ ± 1).


If the first and the nth term of a G.P. are a ad b, respectively, and if P is the product of n terms, prove that P2 = (ab)n.


Show that the ratio of the sum of first n terms of a G.P. to the sum of terms from (n + 1)th to (2n)th term is `1/r^n`.


If f is a function satisfying f (x +y) = f(x) f(y) for all x, y ∈ N such that f(1) = 3 and `sum_(x = 1)^n` f(x) = 120, find the value of n.


The first term of a G.P. is 1. The sum of the third term and fifth term is 90. Find the common ratio of G.P.


Find : 

nth term of the G.P.

\[\sqrt{3}, \frac{1}{\sqrt{3}}, \frac{1}{3\sqrt{3}}, . . .\]


Find :

the 10th term of the G.P.

\[\sqrt{2}, \frac{1}{\sqrt{2}}, \frac{1}{2\sqrt{2}}, . . .\]


If the G.P.'s 5, 10, 20, ... and 1280, 640, 320, ... have their nth terms equal, find the value of n.


If \[\frac{a + bx}{a - bx} = \frac{b + cx}{b - cx} = \frac{c + dx}{c - dx}\] (x ≠ 0), then show that abc and d are in G.P.


The sum of first three terms of a G.P. is \[\frac{39}{10}\] and their product is 1. Find the common ratio and the terms.

 

Find the sum of the following geometric series:

\[\sqrt{2} + \frac{1}{\sqrt{2}} + \frac{1}{2\sqrt{2}} + . . .\text { to 8  terms };\]


Find the sum of the following geometric series:

\[\frac{2}{9} - \frac{1}{3} + \frac{1}{2} - \frac{3}{4} + . . . \text { to 5 terms };\]


Find the sum of the following geometric series:

x3, x5, x7, ... to n terms


Evaluate the following:

\[\sum^n_{k = 1} ( 2^k + 3^{k - 1} )\]


The sum of n terms of the G.P. 3, 6, 12, ... is 381. Find the value of n.


The 4th and 7th terms of a G.P. are \[\frac{1}{27} \text { and } \frac{1}{729}\] respectively. Find the sum of n terms of the G.P.


Find the sum of the following serie to infinity:

`2/5 + 3/5^2 +2/5^3 + 3/5^4 + ... ∞.`


Find an infinite G.P. whose first term is 1 and each term is the sum of all the terms which follow it.


If a, b, c are in G.P., prove that log a, log b, log c are in A.P.


Insert 6 geometric means between 27 and  \[\frac{1}{81}\] .


If A1, A2 be two AM's and G1G2 be two GM's between and b, then find the value of \[\frac{A_1 + A_2}{G_1 G_2}\]


The fractional value of 2.357 is 


The sum of an infinite G.P. is 4 and the sum of the cubes of its terms is 92. The common ratio of the original G.P. is 


Given that x > 0, the sum \[\sum^\infty_{n = 1} \left( \frac{x}{x + 1} \right)^{n - 1}\] equals 


The product (32), (32)1/6 (32)1/36 ... to ∞ is equal to 


Mark the correct alternative in the following question: 

Let S be the sum, P be the product and R be the sum of the reciprocals of 3 terms of a G.P. Then p2R3 : S3 is equal to 


For the G.P. if r = `1/3`, a = 9 find t7


For what values of x, the terms `4/3`, x, `4/27` are in G.P.?


The number of bacteria in a culture doubles every hour. If there were 50 bacteria originally in the culture, how many bacteria will be there at the end of 5th hour?


The numbers x − 6, 2x and x2 are in G.P. Find 1st term


For the following G.P.s, find Sn.

p, q, `"q"^2/"p", "q"^3/"p"^2,` ...


If the A.M. of two numbers exceeds their G.M. by 2 and their H.M. by `18/5`, find the numbers.


Select the correct answer from the given alternative.

If common ratio of the G.P is 5, 5th term is 1875, the first term is -


Answer the following:

Find five numbers in G.P. such that their product is 243 and sum of second and fourth number is 10.


Answer the following:

For a sequence Sn = 4(7n – 1) verify that the sequence is a G.P.


The third term of a G.P. is 4, the product of the first five terms is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×