मराठी

Which Term of the Progression 18, −12, 8, ... is 512 729 ?

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प्रश्न

Which term of the progression 18, −12, 8, ... is \[\frac{512}{729}\] ?

 
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उत्तर

\[\text { Here, first term }, a = 18 \]

\[\text { and common ratio }, r = \frac{- 2}{3}\]

\[\text { Let the } n^{th} \text { term be } \frac{512}{729} . \]

\[ \therefore a r^{n - 1} = \frac{512}{729}\]

\[ \Rightarrow \left( 18 \right) \left( \frac{- 2}{3} \right)^{n - 1} = \frac{512}{729}\]

\[ \Rightarrow \left( \frac{- 2}{3} \right)^{n - 1} = \frac{512}{729} \times \frac{1}{18} = \frac{256}{6561}\]

\[ \Rightarrow \left( \frac{- 2}{3} \right)^{n - 1} = \left( \frac{- 2}{3} \right)^8 \]

\[ \Rightarrow n - 1 = 8 \]

\[ \Rightarrow n = 9\]

\[\text { Thus, the } 9^{th} \text { term of the given G . P . is } \frac{512}{729} .\]

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पाठ 20: Geometric Progression - Exercise 20.1 [पृष्ठ १०]

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आर.डी. शर्मा Mathematics [English] Class 11
पाठ 20 Geometric Progression
Exercise 20.1 | Q 7 | पृष्ठ १०

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