मराठी

The first term of a G.P. is 1. The sum of the third term and fifth term is 90. Find the common ratio of G.P. - Mathematics

Advertisements
Advertisements

प्रश्न

The first term of a G.P. is 1. The sum of the third term and fifth term is 90. Find the common ratio of G.P.

बेरीज
Advertisements

उत्तर

Let a and r be the first term and the common ratio of the G.P. respectively.

∴ a = 1

a3 = ar2 = r2

a5 = ar4 = r4

∴ r2 + r4 = 90

⇒ r4 + r2 – 90 = 0

= `r^2 = (-1 + sqrt(1 + 360))/2 = (-1± sqrt361)/2 =(-1 ± 19)/(2) = -10 or 9`

∴ r = ± 3        (Taking real roots)

Thus, the common ratio of the G.P. is ±3.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 9: Sequences and Series - Miscellaneous Exercise [पृष्ठ १९९]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 11
पाठ 9 Sequences and Series
Miscellaneous Exercise | Q 9 | पृष्ठ १९९

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

The 5th, 8th and 11th terms of a G.P. are p, q and s, respectively. Show that q2 = ps.


For what values of x, the numbers  `-2/7, x, -7/2` are in G.P?


Given a G.P. with a = 729 and 7th term 64, determine S7.


If the pth, qth and rth terms of a G.P. are a, b and c, respectively. Prove that `a^(q - r) b^(r-p) c^(p-q) = 1`.


If the first and the nth term of a G.P. are a ad b, respectively, and if P is the product of n terms, prove that P2 = (ab)n.


The sum of two numbers is 6 times their geometric mean, show that numbers are in the ratio `(3 + 2sqrt2) ":" (3 - 2sqrt2)`.


Show that the sequence <an>, defined by an = \[\frac{2}{3^n}\], n ϵ N is a G.P.


Find :

the 8th term of the G.P. 0.3, 0.06, 0.012, ...


Find three numbers in G.P. whose sum is 38 and their product is 1728.


Find the sum of the following geometric series:

1, −a, a2, −a3, ....to n terms (a ≠ 1)


Find the sum of the following series:

0.5 + 0.55 + 0.555 + ... to n terms.


The sum of n terms of the G.P. 3, 6, 12, ... is 381. Find the value of n.


A G.P. consists of an even number of terms. If the sum of all the terms is 5 times the sum of the terms occupying the odd places. Find the common ratio of the G.P.


Find the sum of the following series to infinity:

10 − 9 + 8.1 − 7.29 + ... ∞


Prove that: (21/4 . 41/8 . 81/16. 161/32 ... ∞) = 2.


Three numbers are in A.P. and their sum is 15. If 1, 3, 9 be added to them respectively, they form a G.P. Find the numbers.


If a, b, c are in G.P., prove that:

(a + 2b + 2c) (a − 2b + 2c) = a2 + 4c2.


If a, b, c, d are in G.P., prove that:

(b + c) (b + d) = (c + a) (c + d)


If a, b, c are in G.P., prove that the following is also in G.P.:

a2 + b2, ab + bc, b2 + c2


If a, b, c, d are in G.P., prove that:

(a2 + b2), (b2 + c2), (c2 + d2) are in G.P.


If \[\frac{1}{a + b}, \frac{1}{2b}, \frac{1}{b + c}\] are three consecutive terms of an A.P., prove that a, b, c are the three consecutive terms of a G.P.


Find the geometric means of the following pairs of number:

2 and 8


Find the geometric means of the following pairs of number:

a3b and ab3


The sum of two numbers is 6 times their geometric means, show that the numbers are in the ratio `(3+2sqrt2):(3-2sqrt2)`.


The value of 91/3 . 91/9 . 91/27 ... upto inf, is 


Check whether the following sequence is G.P. If so, write tn.

`sqrt(5), 1/sqrt(5), 1/(5sqrt(5)), 1/(25sqrt(5))`, ...


Which term of the G.P. 5, 25, 125, 625, … is 510?


The numbers x − 6, 2x and x2 are in G.P. Find nth term


For the following G.P.s, find Sn.

`sqrt(5)`, −5, `5sqrt(5)`, −25, ...


For a sequence, if Sn = 2(3n –1), find the nth term, hence show that the sequence is a G.P.


If Sn, S2n, S3n are the sum of n, 2n, 3n terms of a G.P. respectively, then verify that Sn (S3n – S2n) = (S2n – Sn)2.


Find: `sum_("r" = 1)^10 5 xx 3^"r"`


Find `sum_("r" = 0)^oo (-8)(-1/2)^"r"` 


Answer the following:

Find five numbers in G.P. such that their product is 243 and sum of second and fourth number is 10.


Answer the following:

If for a G.P. t3 = `1/3`, t6 = `1/81` find r


Answer the following:

If a, b, c are in G.P. and ax2 + 2bx + c = 0 and px2 + 2qx + r = 0 have common roots then verify that pb2 – 2qba + ra2 = 0


Answer the following:

If p, q, r, s are in G.P., show that (p2 + q2 + r2) (q2 + r2 + s2) = (pq + qr + rs)2   


If the sum of an infinite GP a, ar, ar2, ar3, ...... . is 15 and the sum of the squares of its each term is 150, then the sum of ar2, ar4, ar6, .... is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×