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Find : ∑r=1∞4(0.5)r - Mathematics and Statistics

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प्रश्न

Find : `sum_("r" = 1)^oo 4(0.5)^"r"`

बेरीज
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उत्तर

`sum_("r" = 1)^oo 4(0.5)^"r" = 4 sum_("r" = 1)^oo (0.5)^"r"`

= 4[0.5 + (0.5)2 + (0.5)3 + ...]

= `4[5/10 + (5/10)^2 + (5/10)^3 + ...]`

= `4[1/2 + (1/2)^2 + (1/2)^3 + ....]`    ...(1)

The terms `1/2, (1/2)^2, (1/2)^3` ... form a G.P. with

a = `1/2`, r = `1/2`

Since |r| = `|1/2| = 1/2 < 1`, the sum to infinity of this G.P. exist and

S = `"a"/(1 - "r")`

= `((1/2))/(1 - (1/2))` = 1

∴ from (1),

`sum_("r" = 1)^oo 4(0.5)^"r"` = 4 x 1 = 4.

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पाठ 2: Sequences and Series - Exercise 2.3 [पृष्ठ ३४]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
पाठ 2 Sequences and Series
Exercise 2.3 | Q 6. (i) | पृष्ठ ३४

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