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Question
Find the area of the region in the first quadrant enclosed by x-axis, line x = `sqrt3` y and the circle x2 + y2 = 4.
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Solution
The area of the region bounded by the circle, `x^2 + y^2 = 4, x = sqrt3` and the x-axis is the area OAB.
The point of intersection of the line and the circle in the first quadrant is .`(sqrt3,1)`
Area OAB = Area ΔOCA + Area ACB
Therefore, required area enclosed = 32 + π3 - 32 = π3 square units
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