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Find the area of the region bounded by the ellipse x24+y29=1. - Mathematics

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Question

Find the area of the region bounded by the ellipse `x^2/4 + y^2/9 = 1.`

Sum
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Solution

The given ellipse is `x^2/4 + y^2/9 = 1`

Since the given curve is symmetrical about both axes.

∴ Area of ellipse = 4 areas (OABO)

∴ Requied area = 4 Area (OABO) = `4 int_0^3 x  dy`     ...[by taking horizontal strips]

`4 int_0^3 2/3 sqrt (9 - y^2)  dx`         `...[x^2/4 + y^2/9 = 1 ⇒ x^2/4 = 1 - y^2/9 ⇒ x = 2/3 sqrt (9 - y^2) (∵ x > 0)]`

`= 4 xx 2/3 [y/2 sqrt (9 - y^2) + 9/2 sin^-1  y/3]_0^3`

`= 4 xx 2/3 [(3/2 (0) + 9/2 sin^-1 (1)) - (0 - 0)]`

`= 4 xx 2/3 [9/2 (pi/2)]`

`= 4 xx (3pi)/2`

= 6π square units 

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Chapter 8: Application of Integrals - Exercise 8.1 [Page 366]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 8 Application of Integrals
Exercise 8.1 | Q 5 | Page 366

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