English

Find the area of the region bounded by the following curves, the X-axis and the given lines: 2y + x = 8, x = 2, x = 4

Advertisements
Advertisements

Question

Find the area of the region bounded by the following curves, the X-axis and the given lines: 2y + x = 8, x = 2, x = 4

Sum
Advertisements

Solution

Let A be the required area.
Consider the equation 2y + x = 8

i.e., y = `(8 - x)/(2)`

∴ A = `int_2^4 y*dx`

= `int_2^4 (8 - x)/(2)*dx`

= `(1)/(2) int_2^4 (8 - x)*dx`

= `(1)/(2)[8x - x^2/2]_2^4`

= `(1)/(2)[(8 xx 4 - 4^2/2) - (8 xx 2 - 2^2/2)]`

= `(1)/(2)(32 - 8) - (16 - 2)]`

= `(1)/(2)(24 - 14)`

= `(1)/(2) xx 10`
∴ A = 5 sq. units.

shaalaa.com
  Is there an error in this question or solution?
Chapter 7: Applications of Definite Integration - Exercise 7.1 [Page 157]

APPEARS IN

Balbharati Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
Chapter 7 Applications of Definite Integration
Exercise 7.1 | Q 1.5 | Page 157

RELATED QUESTIONS

Find the area of the region bounded by the curve y2 = x and the lines x = 1, x = 4 and the x-axis.


Find the area of the region bounded by x2 = 4yy = 2, y = 4 and the y-axis in the first quadrant.


Find the area of the region bounded by the parabola y = x2 and y = |x| .


Find the area under the given curve and given line:

y = x2, x = 1, x = 2 and x-axis


Find the area enclosed between the parabola y2 = 4ax and the line y mx


Using integration, find the area of the region {(x, y) : x2 + y2 ≤ 1 ≤ x + y}.


Find the area of the region bounded by the following curves, the X-axis, and the given lines:

y = `sqrt(6x + 4), x = 0, x = 2`


Choose the correct alternative :

Area of the region bounded by the curve x2 = y, the X-axis and the lines x = 1 and x = 3 is _______.


Area of the region bounded by y = x4, x = 1, x = 5 and the X-axis is _______.


Fill in the blank :

Area of the region bounded by x2 = 16y, y = 1, y = 4 and the Y-axis, lying in the first quadrant is _______.


State whether the following is True or False :

The area of the portion lying above the X-axis is positive.


Choose the correct alternative:

Area of the region bounded by y2 = 16x, x = 1 and x = 4 and the X axis, lying in the first quadrant is ______


State whether the following statement is True or False:

The area of portion lying below the X axis is negative


State whether the following statement is True or False:

The area bounded by the curve y = f(x) lies on the both sides of the X-axis is `|int_"a"^"b" "f"(x)  "d"x| + |int_"b"^"c" "f"(x)  "d"x|`


The area bounded by the parabola x2 = 9y and the lines y = 4 and y = 9 in the first quadrant is ______


The area of the circle x2 + y2 = 16 is ______


Find the area of the region bounded by the curve 4y = 7x + 9, the X-axis and the lines x = 2 and x = 8


Find the area of the circle x2 + y2 = 62 


The area bounded by y = `27/x^3`, X-axis and the ordinates x = 1, x = 3 is ______


`int_0^log5 (e^xsqrt(e^x - 1))/(e^x + 3)` dx = ______ 


The ratio in which the area bounded by the curves y2 = 8x and x2 = 8y is divided by the line x = 2 is ______ 


The area bounded by the X-axis, the curve y = f(x) and the lines x = 1, x = b is equal to `sqrt("b"^2 + 1) - sqrt(2)` for all b > 1, then f(x) is ______.


Equation of a common tangent to the circle, x2 + y2 – 6x = 0 and the parabola, y2 = 4x, is:


The area included between the parabolas y2 = 4a(x +a) and y2 = 4b(x – a), b > a > 0, is


The area of the circle `x^2 + y^2 = 16`, exterior to the parabola `y = 6x`


Find the area between the two curves (parabolas)

y2 = 7x and x2 = 7y.


The area (in sq.units) of the part of the circle x2 + y2 = 36, which is outside the parabola y2 = 9x, is ______.


The area bounded by the curve, y = –x, X-axis, x = 1 and x = 4 is ______.


The area bounded by the curve `y = 3/2sqrtx`, the line x = 1 and x-axis is ______ sq. units.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×