English

Find the Area of the Region Bounded by the Parabola Y = X2 and Y = X .

Advertisements
Advertisements

Question

Find the area of the region bounded by the parabola y = x2 and y = |x| .

Advertisements

Solution

The area bounded by the parabola, x2 = y,and the line, y = |x| , can be represented as

The given area is symmetrical about y-axis.

∴ Area OACO = Area ODBO

The point of intersection of parabola, x2 = y, and line, x, is A (1, 1).

Area of OACO = Area ΔOAM – Area OMACO

shaalaa.com
  Is there an error in this question or solution?
Chapter 8: Application of Integrals - Exercise 8.1 [Page 366]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 8 Application of Integrals
Exercise 8.1 | Q 9 | Page 366

RELATED QUESTIONS

Find the area of the region bounded by x2 = 4yy = 2, y = 4 and the y-axis in the first quadrant.


Find the area under the given curve and given line:

y = x2, x = 1, x = 2 and x-axis


Find the area between the curves y = x and y = x2


Find the area of the region lying in the first quadrant and bounded by y = 4x2x = 0, y = 1 and = 4


Sketch the graph of y = |x + 3| and evaluate `int_(-6)^0 |x + 3|dx`


Find the area enclosed between the parabola y2 = 4ax and the line y mx


Find the area of the smaller region bounded by the ellipse `x^2/9 + y^2/4` and the line `x/3 + y/2 = 1`


Using integration, find the area of the region {(x, y) : x2 + y2 ≤ 1 ≤ x + y}.


Find the area of the region bounded by the following curves, the X-axis, and the given lines:

y = `sqrt(6x + 4), x = 0, x = 2`


Find the area of the region bounded by the following curves, the X-axis and the given lines: y = `sqrt(16 - x^2)`, x = 0, x = 4


Find the area of the region bounded by the following curves, the X-axis and the given lines: 2y + x = 8, x = 2, x = 4


Find the area of the region bounded by the following curves, the X-axis and the given lines:

y = x2 + 1, x = 0, x = 3


The area of the region bounded by y2 = 4x, the X-axis and the lines x = 1 and x = 4 is _______.


Area of the region bounded by y = x4, x = 1, x = 5 and the X-axis is _______.


State whether the following is True or False :

The area bounded by the curve y = f(x), X-axis and lines x = a and x = b is `|int_"a"^"b" f(x)*dx|`.


State whether the following is True or False :

The area of the portion lying above the X-axis is positive.


The area of the region bounded by the curve y2 = x and the Y axis in the first quadrant and lines y = 3 and y = 9 is ______


Find the area of the region bounded by the parabola y2 = 25x and the line x = 5


Find the area of the region bounded by the curve y = `sqrt(36 - x^2)`, the X-axis lying in the first quadrant and the lines x = 0 and x = 6


The area bounded by y = `27/x^3`, X-axis and the ordinates x = 1, x = 3 is ______


The area enclosed between the curve y = loge(x + e) and the coordinate axes is ______.


`int_0^log5 (e^xsqrt(e^x - 1))/(e^x + 3)` dx = ______ 


Area bounded by the curve xy = 4, X-axis between x = 1, x = 5 is ______.


Area under the curve `y=sqrt(4x+1)` between x = 0 and x = 2 is ______.


The area enclosed by the parabolas x = y2 - 1 and x = 1 - y2 is ______.


Which equation below represents a parabola that opens upward with a vertex at (0, – 5)?


The area (in sq.units) of the part of the circle x2 + y2 = 36, which is outside the parabola y2 = 9x, is ______.


If area of the region bounded by y ≥ cot( cot–1|In|e|x|) and x2 + y2 – 6 |x| – 6|y| + 9 ≤ 0, is λπ, then λ is ______.


The figure shows as triangle AOB and the parabola y = x2. The ratio of the area of the triangle AOB to the area of the region AOB of the parabola y = x2 is equal to ______.


The area (in sq. units) of the region {(x, y) : y2 ≥ 2x and x2 + y2 ≤ 4x, x ≥ 0, y ≥ 0} is ______.


Find the area of the regions bounded by the line y = −2x, the X-axis and the lines x = −1 and x = 2.


What is the area of an arbitrary elementary vertical strip of height \[y\] and width \[dx\]?


What is the total area bounded by \[y=f(x)\], the \[x\]-axis, and the ordinates \[x=a\] and \[x=b\], when the region is above the \[x\]-axis?


Which expression gives physical area when the curve \[y=f(x)\] lies below the \[x\]-axis from \[x=a\] to \[x=b\]?


For the ellipse \[\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\], which expression for \[y\] is obtained before selecting the first-quadrant branch?


Why is the area enclosed by \[\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\] written as \[4\int_0^a y\,dx\]?


Which antiderivative is used in evaluating \[\int \sqrt{a^2-x^2}\,dx\] for the ellipse area?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×