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Find area of the region bounded by the parabola x2 = 4y, the Y-axis lying in the first quadrant and the lines y = 3 - Mathematics and Statistics

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Question

Find area of the region bounded by the parabola x2 = 4y, the Y-axis lying in the first quadrant and the lines y = 3

Sum
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Solution


Given equation of the parabola is x2 = 4y

∴ x = `2sqrt(y)`    ......[∵ In first quadrant x > 0]

∴ Required area = `int_0^3 2sqrt(y)  "d"y`

= `2 int_0^3 sqrt(y)  "d"y`

= `3[(y^(3/2))/(3/2)]_0^3`

= `4/3[(3)^(3/2) - 0]`

= `4/3(3sqrt(3))`

= `4sqrt(3)` sq.units

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Chapter 1.7: Application of Definite Integration - Q.2

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SCERT Maharashtra Mathematics and Statistics (Commerce) [English] 12 Standard HSC
Chapter 1.7 Application of Definite Integration
Q.2 | Q 9

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