हिंदी

Find area of the region bounded by the parabola x2 = 4y, the Y-axis lying in the first quadrant and the lines y = 3

Advertisements
Advertisements

प्रश्न

Find area of the region bounded by the parabola x2 = 4y, the Y-axis lying in the first quadrant and the lines y = 3

योग
Advertisements

उत्तर


Given equation of the parabola is x2 = 4y

∴ x = `2sqrt(y)`    ......[∵ In first quadrant x > 0]

∴ Required area = `int_0^3 2sqrt(y)  "d"y`

= `2 int_0^3 sqrt(y)  "d"y`

= `3[(y^(3/2))/(3/2)]_0^3`

= `4/3[(3)^(3/2) - 0]`

= `4/3(3sqrt(3))`

= `4sqrt(3)` sq.units

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1.7: Application of Definite Integration - Q.2

संबंधित प्रश्न

Find the area of the region bounded by y2 = 9x, x = 2, x = 4 and the x-axis in the first quadrant.


Find the area of the region bounded by x2 = 4yy = 2, y = 4 and the y-axis in the first quadrant.


Find the area of the region bounded by the ellipse  `x^2/16 + y^2/9 = 1.`


Find the area of the region bounded by the parabola y = x2 and y = |x| .


Find the area bounded by the curve x2 = 4y and the line x = 4– 2


Area of the region bounded by the curve y2 = 4x, y-axis and the line y = 3 is ______.


Find the area under the given curve and given line:

y = x2, x = 1, x = 2 and x-axis


Find the area under the given curve and given line:

y = x4, x = 1, x = 5 and x-axis


Find the area enclosed between the parabola y2 = 4ax and the line y mx


Find the area of the smaller region bounded by the ellipse `x^2/9 + y^2/4` and the line `x/3 + y/2 = 1`


Find the area of the region {(x, y) : y2 ≤ 4x, 4x2 + 4y2 ≤ 9}


Using integration, find the area of the region {(x, y) : x2 + y2 ≤ 1 ≤ x + y}.


Find the area of the region. 

{(x,y) : 0 ≤ y ≤ x, 0 ≤ y ≤ x + 2 ,-1 ≤ x ≤ 3} .


Find the area of the region bounded by the following curves, the X-axis, and the given lines:

y = `sqrt(6x + 4), x = 0, x = 2`


Area of the region bounded by y = x4, x = 1, x = 5 and the X-axis is _______.


Using definite integration, area of the circle x2 + y2 = 49 is _______.


The area of the region bounded by y2 = 4x, the X-axis and the lines x = 1 and x = 4 is _______.


If the curve, under consideration, is below the X-axis, then the area bounded by curve, X-axis and lines x = a, x = b is positive.


Choose the correct alternative:

Area of the region bounded by the curve x2 = 8y, the positive Y-axis lying in the first quadrant and the lines y = 4 and y = 9 is ______


State whether the following statement is True or False:

The area of portion lying below the X axis is negative


State whether the following statement is True or False:

The area bounded by the curve y = f(x) lies on the both sides of the X-axis is `|int_"a"^"b" "f"(x)  "d"x| + |int_"b"^"c" "f"(x)  "d"x|`


The area of the shaded region bounded by two curves y = f(x), and y = g(x) and X-axis is `int_"a"^"b" "f"(x) "d"x + int_"a"^"b" "g"(x)  "d"x`


The area of the region x2 = 4y, y = 1 and y = 2 and the Y axis lying in the first quadrant is ______


Find the area of the region bounded by the curve 4y = 7x + 9, the X-axis and the lines x = 2 and x = 8


Find area of the region bounded by the parabola x2 = 36y, y = 1 and y = 4, and the positive Y-axis


If a2 + b2 + c2 = – 2 and f(x) = `|(1 + a^2x, (1 + b^2)x, (1 + c^2)x),((1 + a^2)x, 1 + b^2x, (1 + c^2)x),((1 + a^2)x, (1 + b^2)x, 1 + c^2x)|` then f(x) is a polynomial of degree


The slope of a tangent to the curve y = 3x2 – x + 1 at (1, 3) is ______.


Area in first quadrant bounded by y = 4x2, x = 0, y = 1 and y = 4 is ______.


Area bounded by the curves y = `"e"^(x^2)`, the x-axis and the lines x = 1, x = 2 is given to be α square units. If the area bounded by the curve y = `sqrt(ℓ "n"x)`, the x-axis and the lines x = e and x = e4 is expressed as (pe4 – qe – α), (where p and q are positive integers), then (p + q) is ______.


Area bounded by y = sec2x, x = `π/6`, x = `π/3` and x-axis is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×