English

Solve the following: Find the area of the region bounded by the curve x2 = 25y, y = 1, y = 4 and the Y-axis. - Mathematics and Statistics

Advertisements
Advertisements

Question

Solve the following:

Find the area of the region bounded by the curve x2 = 25y, y = 1, y = 4 and the Y-axis.

Sum
Advertisements

Solution


The given equation of the curve is x2 = 25y.

∴ `5sqrt(y)`          ...(∵ In first quadrant, x > 0)

Required area = `int_1^4x.dy`

∴ A = `int_1^4 5sqrt(y).dy`

∴ A = `5int_1^4 y^(1/2).dy`

∴ A = `5[(y^(3/2))/(3/2)]_1^4`

∴ A = `5 × 2/3 [4^(3/2) - 1]`

∴ A = `10/3 [(2^2)^(3/2) - 1]`

∴ A = `10/3 [8 - 1]`

∴ A = `10/3 × 7`

∴ A = `70/3` sq. units

shaalaa.com
  Is there an error in this question or solution?
Chapter 7: Applications of Definite Integration - Miscellaneous Exercise 7 [Page 158]

APPEARS IN

Balbharati Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
Chapter 7 Applications of Definite Integration
Miscellaneous Exercise 7 | Q 4.6 | Page 158

RELATED QUESTIONS

Find the area of the region bounded by the ellipse  `x^2/16 + y^2/9 = 1.`


Area lying in the first quadrant and bounded by the circle x2 + y2 = 4 and the lines x = 0 and x = 2 is ______.


Find the area of the smaller region bounded by the ellipse \[\frac{x^2}{9} + \frac{y^2}{4} = 1\] and the line \[\frac{x}{3} + \frac{y}{2} = 1 .\]


Find the area of the region bounded by the parabola y2 = 16x and the line x = 4. 


Draw a rough sketch and find the area bounded by the curve x2 = y and x + y = 2.


Find the area of the region bounded by the following curves, the X-axis, and the given lines:

y = `sqrt(6x + 4), x = 0, x = 2`


Find the area of the region bounded by the following curves, the X-axis and the given lines:

y = x2 + 1, x = 0, x = 3


Find the area of the region bounded by the following curve, the X-axis and the given line:

y = 2 – x2, x = –1, x = 1


Area of the region bounded by x2 = 16y, y = 1 and y = 4 and the Y-axis, lying in the first quadrant is _______.


Using definite integration, area of the circle x2 + y2 = 49 is _______.


Fill in the blank :

The area of the region bounded by the curve x2 = y, the X-axis and the lines x = 3 and x = 9 is _______.


The area of the region bounded by y2 = 4x, the X-axis and the lines x = 1 and x = 4 is _______.


Solve the following :

Find the area of the region bounded by the curve xy = c2, the X-axis, and the lines x = c, x = 2c.


Choose the correct alternative:

Area of the region bounded by the curve x2 = 8y, the positive Y-axis lying in the first quadrant and the lines y = 4 and y = 9 is ______


Choose the correct alternative:

Area of the region bounded by x = y4, y = 1 and y = 5 and the Y-axis lying in the first quadrant is ______


State whether the following statement is True or False:

The area bounded by the curve y = f(x) lies on the both sides of the X-axis is `|int_"a"^"b" "f"(x)  "d"x| + |int_"b"^"c" "f"(x)  "d"x|`


The area of the circle x2 + y2 = 16 is ______


The area of the region x2 = 4y, y = 1 and y = 2 and the Y axis lying in the first quadrant is ______


Find the area of the region bounded by the curve y = `sqrt(2x + 3)`, the X axis and the lines x = 0 and x = 2


Find the area of the region bounded by the curve 4y = 7x + 9, the X-axis and the lines x = 2 and x = 8


Find area of the region bounded by the parabola x2 = 36y, y = 1 and y = 4, and the positive Y-axis


Find the area of the region bounded by the curve x = `sqrt(25 - y^2)`, the Y-axis lying in the first quadrant and the lines y = 0 and y = 5


Find the area of the circle x2 + y2 = 62 


Find the area of the circle x2 + y2 = 16


The area of the region bounded by the curve y = 4x3 − 6x2 + 4x + 1 and the lines x = 1, x = 5 and X-axis is ____________.


Area bounded by the curve xy = 4, X-axis between x = 1, x = 5 is ______.


Area under the curve `y=sqrt(4x+1)` between x = 0 and x = 2 is ______.


The area bounded by the X-axis, the curve y = f(x) and the lines x = 1, x = b is equal to `sqrt("b"^2 + 1) - sqrt(2)` for all b > 1, then f(x) is ______.


Find the area of the region lying in the first quadrant and bounded by y = 4x2, x = 0,y = 2 and y = 4.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×