English

Find the area of the regions bounded by the line y = −2x, the X-axis and the lines x = −1 and x = 2.

Advertisements
Advertisements

Question

Find the area of the regions bounded by the line y = −2x, the X-axis and the lines x = −1 and x = 2.

Sum
Advertisements

Solution

A = (Area below X-axis) + (Area above X-axis)

Required area A = A1 + |A2|

A = `int_-1^0 (-2x) dx + |int_0^2(-2x)dx|`

= `[-2 x^2/2]_-1^0 + [(2x^2)/2]_0^2`

= `[-x^2]_-1^0 + [x^2]_0^2`

= (0 + 1) + (4 − 0)

A = 5 sq. units

shaalaa.com
  Is there an error in this question or solution?
2023-2024 (March) Official

APPEARS IN

RELATED QUESTIONS

Using integration find the area of the region {(x, y) : x2+y2 2ax, y2 ax, x, y  0}.


Find the area of the region bounded by y2 = 9x, x = 2, x = 4 and the x-axis in the first quadrant.


Find the area of the region bounded by the ellipse `x^2/4 + y^2/9 = 1.`


Find the area of the region in the first quadrant enclosed by x-axis, line x = `sqrt3` y and the circle x2 + y2 = 4.


Find the area under the given curve and given line:

y = x2, x = 1, x = 2 and x-axis


Find the area under the given curve and given line:

y = x4, x = 1, x = 5 and x-axis


Sketch the graph of y = |x + 3| and evaluate `int_(-6)^0 |x + 3|dx`


Find the area bounded by the circle x2 + y2 = 16 and the line `sqrt3 y = x` in the first quadrant, using integration.


Find the area of the region bounded by the following curves, the X-axis and the given lines:

y = x2 + 1, x = 0, x = 3


Find the area of the region bounded by the parabola y2 = 4x and the line x = 3.


Fill in the blank :

Area of the region bounded by x2 = 16y, y = 1, y = 4 and the Y-axis, lying in the first quadrant is _______.


Fill in the blank :

The area of the region bounded by the curve x2 = y, the X-axis and the lines x = 3 and x = 9 is _______.


State whether the following is True or False :

The area of the portion lying above the X-axis is positive.


Solve the following :

Find the area of the region bounded by the curve xy = c2, the X-axis, and the lines x = c, x = 2c.


Choose the correct alternative:

Area of the region bounded by the parabola y2 = 25x and the lines x = 5 is ______


The area of the region x2 = 4y, y = 1 and y = 2 and the Y axis lying in the first quadrant is ______


Find area of the region bounded by the parabola x2 = 4y, the Y-axis lying in the first quadrant and the lines y = 3


If `int_0^(pi/2) log (cos x) "dx" = - pi/2 log 2,` then `int_0^(pi/2) log (cosec x)`dx = ?


`int_0^log5 (e^xsqrt(e^x - 1))/(e^x + 3)` dx = ______ 


Area enclosed between the curve y2(4 - x) = x3 and line x = 4 above X-axis is ______.


The area included between the parabolas y2 = 4a(x +a) and y2 = 4b(x – a), b > a > 0, is


The slope of a tangent to the curve y = 3x2 – x + 1 at (1, 3) is ______.


The area of the region bounded by the curve y = x2, x = 0, x = 3, and the X-axis is ______.


Find the area between the two curves (parabolas)

y2 = 7x and x2 = 7y.


The area (in sq.units) of the part of the circle x2 + y2 = 36, which is outside the parabola y2 = 9x, is ______.


The area bounded by the x-axis and the curve y = 4x – x2 – 3 is ______.


Area bounded by y = sec2x, x = `π/6`, x = `π/3` and x-axis is ______.


The area (in sq. units) of the region {(x, y) : y2 ≥ 2x and x2 + y2 ≤ 4x, x ≥ 0, y ≥ 0} is ______.


The area bounded by the curve, y = –x, X-axis, x = 1 and x = 4 is ______.


The area enclosed by the parabola x2 = 4y and its latus rectum is `8/(6m)` sq units. Then the value of m is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×