English

Find the area of the regions bounded by the line y = −2x, the X-axis and the lines x = −1 and x = 2.

Advertisements
Advertisements

Question

Find the area of the regions bounded by the line y = −2x, the X-axis and the lines x = −1 and x = 2.

Sum
Advertisements

Solution

A = (Area below X-axis) + (Area above X-axis)

Required area A = A1 + |A2|

A = `int_-1^0 (-2x) dx + |int_0^2(-2x)dx|`

= `[-2 x^2/2]_-1^0 + [(2x^2)/2]_0^2`

= `[-x^2]_-1^0 + [x^2]_0^2`

= (0 + 1) + (4 − 0)

A = 5 sq. units

shaalaa.com
  Is there an error in this question or solution?
2023-2024 (March) Official

APPEARS IN

RELATED QUESTIONS

Find the area of the region in the first quadrant enclosed by the x-axis, the line y = x and the circle x2 + y2 = 32.


Find the area of the region in the first quadrant enclosed by x-axis, line x = `sqrt3` y and the circle x2 + y2 = 4.


Find the area of the region bounded by the curve y2 = 4x and the line x = 3


Sketch the graph of y = |x + 3| and evaluate `int_(-6)^0 |x + 3|dx`


Find the area enclosed between the parabola y2 = 4ax and the line y mx


Find the area of the smaller region bounded by the ellipse `x^2/a^2 + y^2/b^2 = 1` and the line `x/a + y/b =   1`


Using the method of integration, find the area of the triangle ABC, coordinates of whose vertices are A (4 , 1), B (6, 6) and C (8, 4).


Find the area bounded by the circle x2 + y2 = 16 and the line `sqrt3 y = x` in the first quadrant, using integration.


Find the area of the region. 

{(x,y) : 0 ≤ y ≤ x, 0 ≤ y ≤ x + 2 ,-1 ≤ x ≤ 3} .


Using integration find the area of the triangle formed by negative x-axis and tangent and normal to the circle `"x"^2 + "y"^2 = 9  "at" (-1,2sqrt2)`.


Find the area of the region bounded by the following curves, the X-axis, and the given lines:

y = `sqrt(6x + 4), x = 0, x = 2`


Find the area of the region bounded by the following curves, the X-axis and the given lines:  2y = 5x + 7, x = 2, x = 8


Choose the correct alternative :

Area of the region bounded by the curve x2 = y, the X-axis and the lines x = 1 and x = 3 is _______.


Area of the region bounded by x2 = 16y, y = 1 and y = 4 and the Y-axis, lying in the first quadrant is _______.


The area of the region bounded by y2 = 4x, the X-axis and the lines x = 1 and x = 4 is _______.


Find the area of the region bounded by y = x2, the X-axis and x = 1, x = 4.


State whether the following statement is True or False:

The area bounded by the curve y = f(x) lies on the both sides of the X-axis is `|int_"a"^"b" "f"(x)  "d"x| + |int_"b"^"c" "f"(x)  "d"x|`


The area of the region bounded by the curve y2 = 4x, the X axis and the lines x = 1 and x = 4 is ______


Find the area of the region bounded by the parabola y2 = 25x and the line x = 5


Find the area of the region bounded by the curve y = `sqrt(2x + 3)`, the X axis and the lines x = 0 and x = 2


Find the area of the region bounded by the curve y = (x2 + 2)2, the X-axis and the lines x = 1 and x = 3


Find the area of the region bounded by the curve y = `sqrt(36 - x^2)`, the X-axis lying in the first quadrant and the lines x = 0 and x = 6


Find the area of the circle x2 + y2 = 62 


The area bounded by y = `27/x^3`, X-axis and the ordinates x = 1, x = 3 is ______


`int_0^log5 (e^xsqrt(e^x - 1))/(e^x + 3)` dx = ______ 


Area under the curve `y=sqrt(4x+1)` between x = 0 and x = 2 is ______.


If a2 + b2 + c2 = – 2 and f(x) = `|(1 + a^2x, (1 + b^2)x, (1 + c^2)x),((1 + a^2)x, 1 + b^2x, (1 + c^2)x),((1 + a^2)x, (1 + b^2)x, 1 + c^2x)|` then f(x) is a polynomial of degree


The area (in sq. units) of the region {(x, y) : y2 ≥ 2x and x2 + y2 ≤ 4x, x ≥ 0, y ≥ 0} is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×