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Question
Ajita starts off from home at 07.00 hours with her father on a scooter that goes at a uniform speed of 30 km/h and drops her at her school after half an hour. She stays in the school till 13.30 hours and takes an auto-rickshaw to return home. The rickshaw has a uniform speed of 10 km/h. Draw the graph for the above situation and also determine the distance of Ajita’s school from her house.
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Solution
Uniform speed of Ajita’s father on scooter = 30 km/h
Time taken by her father to drop Ajita to her school = `1/2`h on 30 min
∴ Distance between Ajita’s school and her home = `30 xx 1/2`= 15 km ...[∵ Distance = Speed × Time]
Distance cover in 1 min = `15/30`
= `1/2` km
= 500 m
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