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Question
A hole diffuses from the p-side to the n-side in a p-n junction. This means that
Options
a bond is broken on the n-side and the electron freed from the bond jumps to the conduction band
a conduction electron on the p-side jumps to a broken bond to complete it
a bond is broken on the n-side and the electron freed from the bond jumps to a broken bond on the p-side to complete it
a bond is broken on the p-side and the electron freed from the bond jumps to a broken bond on the n-side to complete it.
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Solution
a bond is broken on the n-side and the electron freed from the bond jumps to a broken bond on the p-side to complete it
A hole diffuses from the p side to the n side in a p−n junction; that is, an electron moves from the n side to the p side. This implies that a bond is broken on the n side. As the electron travels towards the p side, which is rich in holes, it combines with a hole. A hole is created because of the deficiency of one electron. So, when an electron combines with a hole, it completes that bond.
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