Definitions [16]
Define transition metals.
Elements having partially filled d-orbitals in ground state or in excited state are known as transition elements.
Define lanthanoid contraction.
In the lanthanoids, the electrons are filling the 4f-subshell. On moving from left to right, the nuclear charge increases, and this increase is expected to be compensated by the increase in the magnitude of the shielding effect by the 4f-electrons. However, the f-electrons have very poor shielding effects. With an increasing atomic number in the lanthanoid series, there is a progressive decrease in the atomic as well as ionic radii of trivalent ions from La3+ to Lu3+, and this is known as lanthanoid contraction.
A homogeneous mixture of two or more metals or a metal and a non-metal is called alloy.
The property of transition elements to exhibit more than one oxidation state is called variable oxidation state.
The electrode potential of a half-cell measured under standard conditions is called standard electrode potential.
The extra stability associated with parallel spin electrons in degenerate orbitals is called exchange energy.
The elements in which the last electron enters the (n–1)d subshell are called d-block elements.
The elements which have incompletely filled d-orbitals in their ground state or in any of their common oxidation states are called transition elements.
The elements in which electrons are progressively filled in the 4f or 5f orbitals are called inner transition elements.
The series of elements from cerium (Ce) to lutetium (Lu) in which 4f orbitals are progressively filled are called lanthanoids.
The series of elements from thorium (Th) to lawrencium (Lr) in which 5f orbitals are progressively filled are called actinoids.
The gradual decrease in atomic and ionic radii of lanthanoids with increasing atomic number is called lanthanoid contraction.
Compounds formed when small atoms like H, C or N occupy interstitial spaces in the crystal lattice of metals are called interstitial compounds.
The property of a substance to get attracted in a magnetic field due to the presence of unpaired electrons is called paramagnetism.
The property of a substance to get weakly repelled by a magnetic field due to the absence of unpaired electrons is called diamagnetism.
The property of a substance to be strongly attracted by a magnetic field and retain magnetism is called ferromagnetism.
Theorems and Laws [7]
Statement:
The standard electrode potential values of transition metals depend on ionisation enthalpy, enthalpy of atomisation and hydration enthalpy.
Explanation:
-
More negative E° → stronger reducing agent.
-
Mn and Zn show highly negative E° values.
-
Cu shows positive E° value due to high ionisation enthalpy.
Statement:
Ionisation enthalpy generally increases across a transition series due to increase in effective nuclear charge.
Explanation:
-
Increase in nuclear charge pulls electrons strongly.
-
Variation is not smooth due to extra stability of half-filled and fully filled configurations.
-
Removal of 4s electrons occurs before 3d electrons during ion formation.
Statement:
Transition elements exhibit variable oxidation states due to the comparable energies of ns and (n−1)d orbitals.
Explanation:
-
Both ns and d electrons participate in bonding.
-
Early elements show higher oxidation states.
-
Middle elements show maximum oxidation states.
-
Later elements prefer lower oxidation states.
Example:
Mn shows +2 to +7 oxidation states.
Statement:
The magnetic behaviour of transition metal ions depends on the number of unpaired electrons present in their d-orbitals.
Explanation:
-
Presence of unpaired electrons → Paramagnetic
-
Absence of unpaired electrons → Diamagnetic
-
Magnetic moment increases with increase in number of unpaired electrons
-
Given by formula: \[\mu=\sqrt{n(n+2)}\]
Statement:
Transition metal ions are coloured due to d–d electronic transitions in the presence of ligands.
Explanation:
-
Absorption of visible light promotes electron from lower to higher d-orbital.
-
Colour observed is complementary to absorbed light.
-
d⁰ and d¹⁰ configurations are colourless (e.g., Zn²⁺, Sc³⁺).
Statement:
Transition metals act as catalysts due to their variable oxidation states and ability to form intermediate complexes.
Explanation:
-
They provide alternate reaction pathway.
-
Lower activation energy.
-
Surface adsorption of reactants.
Examples:
- Fe in Haber process
- V₂O₅ in Contact process
- Ni in hydrogenation
Statement:
The most stable oxidation state of lanthanoids is +3 due to the stable 4f electronic configuration.
Explanation:
-
Some show +2 and +4 states due to extra stability of empty, half-filled or fully filled f-orbitals.
-
Ce⁴⁺ and Eu²⁺ are important examples.
Key Points
d-Block Elements:
- Elements in which the last electron enters (n−1)d orbital.
- Located in the middle of the periodic table.
- Also called transition elements.
- Show variable oxidation states, colored compounds, complex formation.
General Electronic Configuration: \[(n-1)d^{1-10}ns^{0-2}\]
f-Block Elements:
- Elements in which the last electron enters (n−2)f orbital.
- Placed separately at the bottom of the periodic table.
- Known as inner transition elements.
Two series:
- Lanthanides (4f): Ce (58) → Lu (71)
- Actinides (5f): Th (90) → Lr (103)
General Electronic Configuration: \[(n-2)f^{1-14}(n-1)d^{0-1}ns^{2}\]
- Located between s-block and p-block elements
- Occupy Groups 3 to 12
- Present in 4 periods (4th to 7th)
Series of d-block:
| Series | Elements |
|---|---|
| 3d | Sc (21) → Zn (30) |
| 4d | Y (39) → Cd (48) |
| 5d | La (57) → Hg (80) |
| 6d | Ac (89) → Cn (112) |
Electronic Configuration:
- The general electronic configuration of 3d-series elements is \[3d^{1-10}4s^{1-2}\].
- The general electronic configuration of 4d-series elements is \[4d^{1-10}5s^{1-2}\].
- The general electronic configuration of 5d-series elements is \[5d^{1-10}6s^{1-2}\].
- The general electronic configuration of 6d-series elements is \[6d^{1-10}7s^{1-2}\].
- All transition elements are d-block elements, but all d-block elements are not transition elements. Zn, Cd and Hg are not transition elements.
| 3d-Series | At. No | Outer E.C | 4d-Series | At. No | Outer E.C | 5d-Series | At. No | Outer E.C | 6d-Series | At. No | Outer E.C |
|---|---|---|---|---|---|---|---|---|---|---|---|
| Sc | 21 | 3d¹4s² | Y | 39 | 4d¹5s² | La | 57 | 5d¹6s² | Ac | 89 | 6d¹7s² |
| Ti | 22 | 3d²4s² | Zr | 40 | 4d²5s² | Hf | 72 | 5d²6s² | Rf | 104 | 6d²7s² |
| V | 23 | 3d³4s² | Nb | 41 | 4d⁴5s¹ | Ta | 73 | 5d³6s² | Db | 105 | 6d³7s² |
| Cr | 24 | 3d⁵4s¹ | Mo | 42 | 4d⁵5s¹ | W | 74 | 5d⁴6s² | Sg | 106 | 6d⁴7s² |
| Mn | 25 | 3d⁵4s² | Tc | 43 | 4d⁵5s² | Re | 75 | 5d⁵6s² | Bh | 107 | 6d⁵7s² |
| Fe | 26 | 3d⁶4s² | Ru | 44 | 4d⁷5s¹ | Os | 76 | 5d⁶6s² | Hs | 108 | 6d⁶7s² |
| Co | 27 | 3d⁷4s² | Rh | 45 | 4d⁸5s¹ | Ir | 77 | 5d⁷6s² | Mt | 109 | 6d⁷7s² |
| Ni | 28 | 3d⁸4s² | Pd | 46 | 4d¹⁰5s⁰ | Pt | 78 | 5d⁹6s¹ | Ds | 110 | 6d⁸7s² |
| Cu | 29 | 3d¹⁰4s¹ | Ag | 47 | 4d¹⁰5s¹ | Au | 79 | 5d¹⁰6s¹ | Rg | 111 | 6d¹⁰7s¹ |
| Zn | 30 | 3d¹⁰4s² | Cd | 48 | 4d¹⁰5s² | Hg | 80 | 5d¹⁰6s² | Cn | 112 | 6d¹⁰7s² |
Atomic and Ionic Radii:
- Atomic and ionic radii of d-block elements are smaller than s-block but larger than p-block elements.
- Within a 3d series, atomic radii decrease for the first five elements (Sc to Mn), then remain almost constant for the next five (Fe to Zn). This is because the increase in ENC (effective nuclear charge) first causes shrinkage, but additional d-electrons increase shielding and counterbalance further shrinkage.
- The 4d and 5d series elements have larger atomic and ionic radii than 3d series elements (due to more electron shells). However, 4d and 5d elements have nearly the same size — due to lanthanoid contraction.
Atomic Volume and Density:
- Atomic volume decreases along a period (as atomic size decreases).
- Density increases along the period.
| Element | Sc | Ti | V | Cr | Mn | Fe | Co | Ni | Cu | Zn |
|---|---|---|---|---|---|---|---|---|---|---|
| Density (g/cm³) | 3.43 | 4.1 | 6.07 | 7.19 | 7.21 | 7.8 | 8.7 | 8.9 | 8.9 | 7.1 |
Melting and Boiling Points:
- All transition elements have high melting points (typically above 900°C) in their solid state.
- Zn, Cd, Hg have abnormally low melting points because their completely filled d-orbitals prevent strong covalent metallic bonding.
- As unpaired electrons increase, metallic bonding strengthens → higher melting point. Tungsten (W) has the highest melting point of all metals.
- Mn and Tc have abnormally low melting points.
Enthalpies of Atomisation:
- Due to strong interatomic attraction, transition metals have high enthalpies of atomisation.
- Greater the number of valence electrons → stronger metallic bonding → higher enthalpy of atomisation.
- Members of 4d and 5d series have greater enthalpy of atomisation than 3d series.
Ionisation Energies:
- IE values of d-block elements lie between those of s-block and p-block elements.
- IE first increases up to Mn, then becomes irregular or constant due to the irregular trend of atomic size in 3d series.
- IE of Zn, Cd, and Hg are abnormally high due to the greater stability of completely filled d-subshells.
- The first two IE values of Ni are lower than Pt → Ni(II) compounds are more thermodynamically stable than Pt(II).
IE₁ order (important anomalies):
- Hg > Cd > Zn
- Au > Cu > Ag
- Pt > Pd > Ni
Oxidation States:
All transition elements except the first and last of each series show a number (variable) of oxidation states.
| Element | Oxidation States |
|---|---|
| Sc | +3 |
| Ti | +2, +3, +4 |
| V | +2, +3, +4, +5 |
| Cr | +2, +3, +4, +5, +6 |
| Mn | +2, +3, +4, +5, +6, +7 |
| Fe | +2, +3, +4, +6 |
| Co | +2, +3, +4 |
| Ni | +2, +3, +4 |
| Cu | +1, +2 |
| Zn | +2 |
- Mn shows the maximum number of oxidation states in the first series (7 states) — because it has 5 unpaired 3d electrons + 2 s-electrons available.
- Higher oxidation states are more stable for heavier members of a group (e.g., Mo(VI) and W(VI) are more stable than Cr(VI)).
- Lower oxidation states are more stable for lighter (3d) members.
Standard Electrode Potential:
- No regular trend exists in E° (M²⁺/M) values because IE and sublimation enthalpies show irregular variation.
- SRP tends to become more positive across a period (left to right) due to increasing IE and decreasing atomic size.
- Within a group, SRP becomes more negative going down.
| E°/V | Sc | Ti | V | Cr | Mn | Fe | Co | Ni | Cu | Zn |
|---|---|---|---|---|---|---|---|---|---|---|
| M²⁺/M | — | −1.63 | −1.18 | −0.90 | −1.18 | −0.44 | −0.28 | −0.25 | +0.34 | −0.76 |
| M³⁺/M²⁺ | — | −0.37 | −0.26 | −0.41 | +1.57 | +0.77 | +1.97 | — | — | — |
- E° for Ni²⁺/Ni and Zn²⁺/Zn are more negative than expected. The high negative value of Ni²⁺/Ni stabilises Ni²⁺ ions. The high negative value for Zn²⁺/Zn is due to the stable, completely filled 3d¹⁰ configuration.
- Cr²⁺ is a strong reducing agent (acts as a reducing agent, gets oxidised to Cr³⁺; the d³ configuration = t₂g³ is very stable).
- Mn³⁺ (d⁴) is an oxidising agent — it gets reduced to Mn²⁺ (d⁵), which has an exactly half-filled d-orbital (extra stability).
- E°(Mn²⁺/Mn) is more negative than expected — due to extra stability of the half-filled 3d⁵ (Mn²⁺) ion.
Coloured Ions: Most of the transition metal compounds (ionic as well as covalent) are coloured both in the solid and in aqueous solution, in contrast to the compounds of s and p-block elements.
| Ion | Configuration | Colour |
|---|---|---|
| Sc³⁺ | 3d⁰ | Colourless |
| Ti⁴⁺ | 3d⁰ | Colourless |
| Ti³⁺ | 3d¹ | Purple |
| V⁴⁺ | 3d¹ | Blue |
| V³⁺ | 3d² | Green |
| V²⁺ | 3d³ | Violet |
| Cr³⁺ | 3d³ | Violet |
| Mn³⁺ | 3d⁴ | Violet |
| Cr²⁺ | 3d⁴ | Blue |
| Mn²⁺ | 3d⁵ | Pink |
| Fe³⁺ | 3d⁵ | Yellow |
| Fe²⁺ | 3d⁶ | Green |
| Co³⁺ | 3d⁶ | Blue |
| Co²⁺ | 3d⁷ | Pink |
| Ni²⁺ | 3d⁸ | Green |
| Cu²⁺ | 3d⁹ | Blue |
| Zn²⁺ | 3d¹⁰ | Colourless |
Magnetic Properties: In the case of transition metals, as they contain unpaired electrons in (n – 1)d orbitals, most of the transition metal ions and their compounds are paramagnetic.
Magnetic moment is calculated by spin only formula viz.
\[\mu=\sqrt{n\left(n+2\right)}\mathrm{~B.M.}\]
where n = number of unpaired electrons
I. K₂Cr₂O₇ (Potassium dichromate)
Preparation: From chromite (FeO·Cr₂O₃)
4FeO·Cr₂O₃ + O₂ → 2Fe₂O₃ + 4Cr₂O₃
4Na₂CO₃ + 2Cr₂O₃ + 3O₂ → 4Na₂Cr₂O₄ + 4CO₂ × 2
4FeO·Cr₂O₃ + 8Na₂CO₃ + 7O₂ → 8Na₂Cr₂O₄ + 2Fe₂O₃ + 8CO₂
2Na₂CrO₄ + 8H₂SO₄ → Na₂Cr₂O₇ + Na₂SO₄ + H₂O
Na₂Cr₂O₇ + 2KCl → K₂Cr₂O₇ + 2NaCl
Properties
Oxidising Properties:
- Liberates I₂ from KI
K₂Cr₂O₇ + 7H₂SO₄ + 6KI → 4K₂SO₄ + Cr₂(SO₄)₃ + 3I₂ + 7H₂O - Oxidises ferrous salts to ferric salts:
K₂Cr₂O₇ + 7H₂SO₄ + 6FeSO₄ → K₂SO₄ + Cr₂(SO₄)₃ + 3Fe₂(SO₄)₃ + 2H₂O - Oxidises H₂S to sulphur:
K₂Cr₂O₇ + 4H₂SO₄ + 3H₂S → K₂SO₄ + Cr₂(SO₄)₃ + 7H₂O + 3S - Oxidises sulphites to sulphates:
K₂Cr₂O₇ + 4H₂SO₄ + 3Na₂SO₃ → K₂SO₄ + Cr₂(SO₄)₃ + 4H₂O + 3Na₂SO₄ - Oxidises nitrites to nitrates:
K₂Cr₂O₇ + 4H₂SO₄ + 3NaNO₂ → K₂SO₄ + Cr₂(SO₄)₃ + 3NaNO₃ + 4H₂O
Structures:

II. Potassium Permanganate (KMnO₄)
Preparation: From Pyrolusite (MnO₂)
2MnO₂ + 4KOH + O₂ → 2K₂MnO₄ + 2H₂O
2MnO₂ + 2K₂CO₃ + O₂ → 2K₂MnO₄ + 2CO₂
MnO₂ + 2KOH + KNO₃ → K₂MnO₄ + KNO₂ + H₂O
3K₂MnO₄ + 2CO₂ → 2KMnO₄ + MnO₂↓ + 2K₂CO₃
Properties
Oxidising Properties:
- Oxidising H₂S to S
2KMnO₄ + 3H₂SO₄ + 5H₂S → K₂SO₄ + 2MnSO₄ + 3H₂O + 5S - Oxidises sulphur dioxide to sulphuric acid
2KMnO₄ + 5SO₂ + 2H₂O → K₂SO₄ + 2MnSO₄ + 2H₂SO₄ - Oxidises oxalates to CO₂
2KMnO₄ + 3H₂SO₄ + 5C₂H₂O₄ → K₂SO₄ + 2MnSO₄ + 8H₂O + 10CO₂ - Oxidises HX to X₂, where X = Cl, Br, I
2KMnO₄ + 3H₂SO₄ + 10HX → K₂SO₄ + 2MnSO₄ + 8H₂O + 5X₂
Structure:

Position and Introduction:
The f-block consists of two series:
- Lanthanoids — fourteen elements from Ce (58) to Lu (71), following Lanthanum (La, 57)
- Actinoids — fourteen elements from Th (90) to Lr (103), following Actinium (Ac, 89)
In lanthanides, electrons enter the penultimate (4f) and pre-penultimate subshells.
General configuration of lanthanoids: [Xe] 4f¹⁻¹⁴ 5d⁰⁻¹ 6s²
Complete Lanthanoid Table:
| Element | Symbol | Z | Outer Config. | Oxidation States | M³⁺ radius (pm) |
|---|---|---|---|---|---|
| Lanthanum | La | 57 | 5d¹, 6s² | +3 | 106 |
| Cerium | Ce | 58 | 4f¹, 5d¹, 6s² | +3, +4 | 103 |
| Praseodymium | Pr | 59 | 4f³, 6s² | +3, +4 | 101 |
| Neodymium | Nd | 60 | 4f⁴, 6s² | +2, +3, +4 | 99 |
| Promethium | Pm | 61 | 4f⁵, 6s² | +3 | 98 |
| Samarium | Sm | 62 | 4f⁶, 6s² | +2, +3 | 96 |
| Europium | Eu | 63 | 4f⁷, 6s² | +2, +3 | 95 |
| Gadolinium | Gd | 64 | 4f⁷, 5d¹, 6s² | +3 | 94 |
| Terbium | Tb | 65 | 4f⁹, 6s² | +3, +4 | 92 |
| Dysprosium | Dy | 66 | 4f¹⁰, 6s² | +3, +4 | 91 |
| Holmium | Ho | 67 | 4f¹¹, 6s² | +3 | 89 |
| Erbium | Er | 68 | 4f¹², 6s² | +3 | 88 |
| Thulium | Tm | 69 | 4f¹³, 6s² | +2, +3 | 87 |
| Ytterbium | Yb | 70 | 4f¹⁴, 6s² | +2, +3 | 86 |
| Lutetium | Lu | 71 | 4f¹⁴, 5d¹, 6s² | +3 | 85 |
La (5d¹6s²), Gd (4f⁷5d¹6s²), and Lu (4f¹⁴5d¹6s²) have a 5d¹ electron — they fill 5d before filling 4f again, due to the stability of half-filled (4f⁷) configuration.
Physical State:
- All are silvery white metals with tensile strength; good conductors of heat and electricity.
- Density ranges from 6.77 to 9.74 g/cm³ and increases with atomic number.
- They readily form alloys with other metals, especially iron.
Oxidation States
- Most common and stable OS = +3
- Some exist in +2 (Sm²⁺, Eu²⁺, Tm²⁺, Yb²⁺) — because they achieve stability trying to reach +3 OS.
- Some exist in +4 (Ce⁴⁺, Pr⁴⁺, Tb⁴⁺, Dy⁴⁺) — because they try to approach +3 from +4; hence, these are good oxidising agents.
- Elements in +2 OS act as reducing agents; in +4 OS act as oxidising agents.
Chemical Behaviour:
Lanthanoids (Ln) react with:
| Reagent | Product |
|---|---|
| Halogens | LnX₃ |
| Carbon (2773 K) | LnC₂ |
| Dilute acids | H₂ gas liberated |
| O₂ | Ln₂O₃ |
| N₂ (Δ) | LnN |
| Sulphur | Ln₂S₃ |
| H₂O | Ln(OH)₃ + H₂ |
- Lanthanoids react with boiling water to give a mixture of oxide and hydride.
- They combine with most non-metals at moderate temperatures.
- Alkalis have no action on them.
Physical Properties:
- Silvery white, soft metals with moderate density
- Good conductors of heat and electricity
Basic Character:
- Hydroxides are ionic and basic
- Basicity decreases from La(OH)₃ to Lu(OH)₃
Ionisation Enthalpy:
- Gradually decreases from La to Lu with irregularities
Oxidation States:
- The most common oxidation state is +3
- Also show +2 and +4
Colour and Spectra:
- Colour due to f–f transitions
Atomic and Ionic Radii (Lanthanoid Contraction):
- Radii decrease from La to Lu
- Due to the poor shielding of the 4f electrons
Magnetic Property:
- Most lanthanoids are paramagnetic
Chemical Reactivity:
- Form:
- Oxides: Ln₂O₃
- Hydroxides: Ln(OH)₃
- Halides: LnX₃
- Nitrides: LnN
- Carbides: LnC₂
General electronic configuration: \[[Xe]4f^{0-14}5d^{0-2}6s^{2}\]
Actinoids are the 14 elements from Th (90) to Lr (103). General configuration: [Rn] 5f¹⁻¹⁴ 6d⁰⁻² 7s²
Complete Actinoid Table:
| Element | Symbol | Z | E.C. | Oxidation States | M³⁺ radius (pm) | M⁴⁺ radius (pm) |
|---|---|---|---|---|---|---|
| Actinium | Ac | 89 | [Rn] 6d¹ 7s² | +3 | 111 | — |
| Thorium | Th | 90 | [Rn] 6d² 7s² | (+3), +4 | — | 99 |
| Protactinium | Pa | 91 | [Rn] 5f² 6d¹ 7s² | +3, +4, +5 | 96 | — |
| Uranium | U | 92 | [Rn] 5f³ 6d¹ 7s² | +3, +4, +5, +6 | 103 | 93 |
| Neptunium | Np | 93 | [Rn] 5f⁴ 6d¹ 7s² | +3, +4, +5, +6, +7 | 101 | 92 |
| Plutonium | Pu | 94 | [Rn] 5f⁶ 7s² | +3, +4, +5, +6, +7 | 100 | 90 |
| Americium | Am | 95 | [Rn] 5f⁷ 7s² | +3, (+4), +5, +6 | 99 | 89 |
| Curium | Cm | 96 | [Rn] 5f⁷ 6d¹ 7s² | +3, (+4) | 99 | 88 |
| Berkelium | Bk | 97 | [Rn] 5f⁹ 7s² | +3, +4 | 98 | 87 |
| Californium | Cf | 98 | [Rn] 5f¹⁰ 7s² | +3 | — | 86 |
| Einsteinium | Es | 99 | [Rn] 5f¹¹ 7s² | +3 | — | — |
| Fermium | Fm | 100 | [Rn] 5f¹² 7s² | +3 | — | — |
| Mendelevium | Md | 101 | [Rn] 5f¹³ 7s² | +3 | — | — |
| Nobelium | No | 102 | [Rn] 5f¹⁴ 7s² | +3 | — | — |
| Lawrencium | Lr | 103 | [Rn] 5f¹⁴ 6d¹ 7s² | +3 | — | — |
- Silvery white metals with high density and high melting/boiling points
- All are radioactive
- Show variable oxidation states (common: +3; higher states in early elements)
- Strong reducing agents and highly reactive
- React with O₂, halogens, H₂, S (similar to lanthanoids)
- React with hot water to form hydroxides and H₂ gas
- Atomic and ionic radii decrease from Ac to Lr (actinoid contraction)
- 5f orbitals show poor shielding → irregular electronic configuration
- Electron distribution in 5f orbitals is less certain than 4f (lanthanoids)
Important Questions [120]
- Assertion (A) : Copper is a non-transition element. Reason (R) : Copper has completely filled d-orbitals in its ground state.
- Out of Cr3+ and Mn3+, Which is a Stronger Oxidising Agent and Why?
- Which Transition Metal of 3d Series Has Positive E° (M2+/M) Value and Why?
- Name the Elements of 3d Transition Series that Show Maximum Number of Oxidation States. Why Does this Happen?
- Define transition metals.
- Account for the following: Mn2+ is more stable than Fe2+ towards oxidation to +3 state.
- Name the element of 3d series which exhibits the largest number of oxidation states. Give reason.
- The elements of 3d transition series are given as: Sc Ti V Cr Mn Fe Co Answer the following: Write the element which shows maximum number of oxidation states. Give reason.
- The elements of 3d transition series are given as: Sc Ti V Cr Mn Fe Co Answer the following: Which element has the highest m.p?
- The elements of 3d transition series are given as: Sc Ti V Cr Mn Fe Co. Answer the following: Which element shows only +3 oxidation state?
- The elements of 3d transition series are given as: Sc Ti V Cr Mn Fe Co. Answer the following: Which element is a strong oxidising agent in +3 oxidation state and why?
- Why do the transition elements have higher enthalpies of atomisation?
- In 3d Series (Sc to Zn), Which Element Has the Lowest Enthalpy of Atomisation and Why?
- How would you account for the following: Transition metals form complex compounds.
- Give reasons: Transition metals show variable oxidation states.
- What are the transition elements? Write two characteristics of the transition elements.
- Which metal in the first transition series (3d series) exhibits + 1 oxidation state most frequently and why?
- Which of the Following Cations Are Coloured in Aqueous Solutions and Why ?
- How Would You Account for the Following? Transition Metals Exhibit Variable Oxidation States.
- Complete the Following Chemical Equations
- Account for the Following: Mn Shows the Highest Oxidation State of +7 with Oxygen but with Fluorine, It Shows Oxidation State of +4.
- Account for the following: Cr2+ is a strong reducing agent.
- Account for the following: Cu+2 salts are coloured, while Zn2+ salts are white.
- Account for the following: Cu+ ion is unstable in aqueous solution.
- From the Given Data of E^0 Values, Answer the Following Questions
- Account for the following: Zn is not considered as a transition element.
- Account for the following: E° value for the Mn3+/Mn2+ couple is much more positive than that for Cr3+/Cr2+.
- Out of Mn3+ and Cr3+, which is more paramagnetic and why ? (Atomic nos. : Mn = 25, Cr = 24)
- Explain why Cu+ ion is not stable in aqueous solutions?
- How is the Variability in Oxidation States of Transition Metals Different from that of the Non-transition Metals? Illustrate with Examples.
- Write the Formula of an Oxo-anion of Chromium (Cr) in Which It Shows the Oxidation State Equal to Its Group Number
- Following Are the Transition Metal Ions of 3d Series:Which Ion is Most Stable in an Aqueous Solution and Why?Which Ion is a Strong Oxidising Agent and Why?Which Ion is Colourless and Why?
- How Would You Account for the Following? Zr (Z = 40) and Hf (Z = 72) Have Almost Identical Radii.
- How would you account for the following? Transition metals and their compounds act as catalysts.
- An Analysis Shows that Feo Has a Non-stoichiometric Composition with Formula Fe0.95o. Give Reason.
- Complete and Balance the Following Chemical Equations Fe^(2+) + Mno_4^(-) + H^+ ->
- Complete and Balance the Following Chemical Equations `Mno_4^(-) + H_2o + I^(-) ->`
- Give reasons: E° value for the Mn3+/Mn2+ couple is much more positive than that for Fe3+/Fe2+.
- Give Reasons Iron Has Higher Enthalpy of Atomization than that of Copper.
- Give Reasons: Sc3+ is Colourless in Aqueous Solution Whereas Ti3+ is Coloured.
- Why Do Transition Elements Show Variable Oxidation States ? in 3d Series (Sc to Zn), Which Elements Shows the Maximum Number of Oxidation State and Why ?
- Account for the Following : 4 Ti4+ is Colourless Whereas 4 V is Coloured in an Aqueous Solutions.
- Why Do Transition Metals Exhibit Higher Enthalpy of Atomization?
- Give reason for the following: The transition metals generally form coloured compounds.
- The magnetic moment is associated with its spin angular momentum and orbital angular momentum. Spin only magnetic moment value of Cr^3+ ion is ______.
- Assertion (A): Cu cannot liberate hydrogen from acids. Reason (R): Because it has positive electrode potential.
- Give reasons for the following statement: Transition metals and most of their compounds show paramagnetic behaviour.
- Give reasons for the following statement: Zn, Cd, and Hg are soft metals.
- Give reason for the following statement: [Ti(H2O)]3+ is coloured while [Sc(H2O)6]3+ is colourless.
- Give reason for the following statement: Physical and chemical properties of the 4d and 5d series of the transition elements are quite similar to expected.
- Account for the following: Transition metals form alloys.
- Why Zn, Cd and Hg are not called transition metals?
- How is the variability in oxidation states of transition metals different from that of p-block elements?
- The oxidation state of Fe in [Fe(CO)5] is ______.
- Which of the following characteristics of transition metals is associated with their catalytic activity?
- Account for the following: Sc3+ is colourless whereas Ti3+ is coloured in an aqueous solution.
- Account for the following: Ce4+ is a strong oxidising agent.
- Assertion (A): Transition metals have high enthalpy of atomisation. Reason (R): Greater number of unpaired electrons in transition metals results in weak metallic bonding.
- Which one among the following metals of the 3d series has the lowest melting point?
- Which of the following transition metals shows +1 and +2 oxidation states?
- Assertion (A): Transition metals show their highest oxidation state with oxygen. Reason (R): The ability of oxygen to form multiple bonds to metals.
- Which property of transition metals enables them to behave as catalysts?
- Complete the following reaction and justify that it is a disproportionation reaction: 3MnOA42−+4HA+⟶――――+――――+2HA2O
- The given graph shows the trends in melting points of transition metals: Explain the reason why Cr has the highest melting point and manganese (Mn) has a lower melting point.
- standard electrode potential values: FeA(aq)3++eA−⟶FeA(aq)2+, E0 = +0.77 V MnOA(aq)−4+8HA++5eA−⟶MnA(aq)2++4HA2OA(l), E0 = +1.51 V What is the cell potential for the redox reaction?
- Which of the following ions has the electronic configuration 3d6?(Atomic number: Mn = 25, Co = 27, Ni = 28)
- A transition element X has an electronic configuration [Ar]4s23d3. Predict its likely oxidation states.
- Consider the following standard electrode potential values: SnA(aq)2++2eA−⟶SnA(s); E0 = −0.14 V What is the cell reaction and potential for the spontaneous reaction that occurs?
- Write the number of unpaired electrons in Cr3+.(Atomic number of Cr = 24)
- Account for the following: Copper has an exceptionally positive EMMEM2+/M0 value.
- Account for the following: Eu2+ with electronic configuration [Xe]4f76s2 is a strong reducing agent.
- How would you account for the following : Transition metals form coloured compounds
- Complete the following equations : 2 Na2CrO4 + 2 H + →
- Complete the reaction mentioning all the products formed: CrA2OA72−+3HA2S+8HA+⟶
- Complete the following equations: Cr2O72- + 14H+ + 6I →
- In the two tetrahedral structures of dichromate ion, ______.
- Why HCl should not be used for potassium permanganate titrations?
- Complete the Following Chemical Equations : Cu + H2so4(Conc.) →
- Complete the Following Equation : 3 M N O 2 − 4 + 4 H + →
- Complete the reaction mentioning all the products formed: 2KMnOA4→Δ
- Account for the Following : Manganese Shows Maximum Number of Oxidation States in 3d Series.
- Name a Member of the Lanthanoid Series that is Well-known to Exhibit +2 Oxidation State.
- Complete the following equations: Cr2O72- + 2OH- →
- Complete the following equations : MnO4- + 4H+ + 3e- →
- Complete the following ionic equation: CrA2OA72−+2OHA−⟶
- Complete the Following Equation
- Complete the following equation: 2MnOX4X−+6HX++5NOX2X−⟶
- E0 Value for Mn3+ Mn2+ Couple is Much More Positive than that for Cr3-/ Cr2-.
- Complete the following equation : MnO4- + 8H+ + 5e- →
- Write the Chemical Equation for the Preparation of 4 Kmno from 2. Mno Why Does Purple Colour of Acidified
- Complete the following chemical equation
- Write the Ionic Equation Showing the Oxidation of Fe(Ii) Salt by Acidified Dichromate Solutions.
- When 2 Mno is Fused with Koh in the Presence of 3 Kno as an Oxidizing Agent, It Gives a Dark Green Compound (A). Compound (A) Disproportionates in Acidic Solution to Give Purple Compound
- Give an example and suggest a reason for the following feature of the transition metal chemistry: The lowest oxide of transition metal is basic, the highest is amphoteric/acidic.
- Indicate the steps in the preparation of KMnO4 from pyrolusite ore.
- Write the Formula of an Oxo-anion of Manganese (Mn) in Which It Shows the Oxidation State Equal to Its Group Number.
- When chromite ore FeCr2O4 is fused with NaOH in presence of air, a yellow-coloured compound (A) is obtained, which on acidification with dilute sulphuric acid gives a compound (B). Compound (B) on reaction with KCl forms an orange coloured crystalline compound (C).
- Using IUPAC norms, write the formula of potassium trioxalatochromate(III).
- Complete the following equations : 2 MnO2 + 4 KOH + O2 →
- Complete the following equations: 2MnO2+4KOH+O2→
- Complete the Following Equations: `2mno_4^(-)+16h^++5s^(2-)Rarr`
- Complete the following chemical equation
- Write any two consequences of Lanthanoid Contraction.
- Zr and Hf have almost similar atomic radii
- Name an Element of Lanthanoid Series Which is Well Knwon to Shown +4 Oxidation State. is It a Strong Oxidising Agent Or Reducing Agent?
- Member of the lanthanoid series which is well known to exhibit +4 oxidation state.
- What is Lanthanoid Contraction? Write The.............
- Account for the Following: Zn, Cd and Hg Are Soft Metals.
- What is lanthanoid contraction?
- How would you account for the following: There is a greater range of oxidation states among the actinoids than among the lanthanides.
- How Would You Account the Following : Highest Fluoride of Mn is Mnf4 Whereas the Highest Oxide is Mn2o7.
- The chemistry of actinoids is more complicated as compared to lanthanoids
- How would you account for the following: Actinoid contraction is greater than lanthanoid contraction.
- Give a Reason for the Following: Actinoids Show Irregularities in Their Electronic Configurations.
- How Do You Prepare: Actinoid Elements Show Wide Range of Oxidation States.
- Give Reasons for the Following: E⁰ Value for (Mn3+|Mn2+) is Highly Positive than that for (Cr3+|Cr2+) Couple.
- Write One Similarity and One Difference Between the Chemistry of Lanthanoid and Actinoid Elements.
- With Reference to Structural Variability and Chemical Reactivity, Write the Differences Between Lanthanoids and Actinoids
- Write on Similarity Between the Chemistry of Lanthanoids and Actinoids.
- Why Do Actinoids Show a Wide Range of Oxidation States?
Concepts [20]
- Transition and Inner Transition Elements
- Position in the Periodic Table - d-block Elements
- Electronic Configurations of the d-block Elements
- Physical Properties of the Transition Elements (d-block)
- Variation in Atomic and Ionic Sizes of Transition Metals (d-block)
- Ionisation Enthalpies of the Transition Elements (d-block)
- Oxidation States of the Transition Elements (d-block)
- Trends in Transition Elements (d-block)
- Chemical Reactivity and Electrode Potentials of Transition Elements (d-Block)
- Magnetic Properties of the Transition Elements (d-block)
- Other Properties of Transition Elements (d-block)
- Important Compounds of Transition Elements
- The Lanthanoids
- Properties of Lanthanoids
- General Characteristics of Lanthanoids
- The Actinoids
- Properties of Actinoids
- General Characteristics of Actinoids
- Applications of d- and f-Block Elements
- Overview of d-block and f-block Elements
