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Question
Write the formula of an oxo-anion of Manganese (Mn) in which it shows the oxidation state equal to its group number.
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Solution
Formula of oxo-anion of manganese (Mn) in which it shows the oxidation state equal to its group number (7) is `Mn_4^(-)`
Mn + (-2 ×4) = -1
Mn - 8 = -1
Mn = +7
Oxidation of Mn in `MnO_4^(-)` is +7 which is equal to its group number 7.
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