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प्रश्न
Write the formula of an oxo-anion of Manganese (Mn) in which it shows the oxidation state equal to its group number.
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उत्तर
Formula of oxo-anion of manganese (Mn) in which it shows the oxidation state equal to its group number (7) is `Mn_4^(-)`
Mn + (-2 ×4) = -1
Mn - 8 = -1
Mn = +7
Oxidation of Mn in `MnO_4^(-)` is +7 which is equal to its group number 7.
संबंधित प्रश्न
Complete the following equation:
\[\ce{2MnO4- + 6H+ + 5NO2- ->}\]
Name the oxometal anions of the first series of the transition metals in which the metal exhibits the oxidation state equal to its group number.
Name a member of the lanthanoid series that is well-known to exhibit +2 oxidation state.
Account for the following :
Manganese shows maximum number of oxidation states in 3d series.
E0 value for Mn3+ Mn2+ couple is much more positive than that for Cr3-/ Cr2-.
Why \[\ce{HCl}\] should not be used for potassium permanganate titrations?
Complete the reaction mentioning all the products formed:
\[\ce{2KMnO4 ->[\Delta]}\]
Complete the reaction mentioning all the products formed:
\[\ce{Cr2O^{2-}7 + 3H2S + 8H^+ ->}\]
Indicate the steps in the preparation of \[\ce{K2Cr2O7}\] from chromite ore.
Indicate the steps in the preparation of \[\ce{K2Cr2O7}\] from chromite ore.
