Advertisements
Advertisements
Question
Name an element of lanthanoid series which is well knwon to shown +4 oxidation state. Is it a strong oxidising agent or reducing agent?
Advertisements
Solution
Ce(Z = 58)
Ce = 4f15d16s2
It is a strong oxidising agent.
⇒ Formationof Ce4+ is favoured because its noble gas configuration, but it is a strong oxidant due to the common +3 state. E° value Ce4+/ Ce3+ =+1.74 V
APPEARS IN
RELATED QUESTIONS
What are chemical twins? Write ‘two’ examples.
Write the electronic configurations of the element with the atomic number 61.
Explain, why lanthanum (Z = 57) forms La3+ ion, while cerium (Z = 58) forms Ce4+ ion?
Explain effects of lanthanoid contraction.
How would you account for the following:
There is a greater range of oxidation states among the actinoids than among the lanthanides.
In lanthanoid the last electron enters (n - 2)f subshell where n is equal to ______.
Write any two consequences of Lanthanoid Contraction.
The lathanide ion that would show colour is ______.
Write a note on lanthanoids.
Why is Mn2+ ion more stable than Fe2+ ion?
(Atomic numbers of Mn = 25 and Fe = 26)
