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प्रश्न
Name an element of lanthanoid series which is well knwon to shown +4 oxidation state. Is it a strong oxidising agent or reducing agent?
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उत्तर
Ce(Z = 58)
Ce = 4f15d16s2
It is a strong oxidising agent.
⇒ Formationof Ce4+ is favoured because its noble gas configuration, but it is a strong oxidant due to the common +3 state. E° value Ce4+/ Ce3+ =+1.74 V
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संबंधित प्रश्न
Compare the chemistry of actinoids with that of the lanthanoids with special reference to oxidation state.
Explain the cause of Lanthanoids contraction.
What is meant by Lanthanide contraction? Write the general electronic configuration of inner transition elements.
Gadolinium belongs to 4f series. It’s atomic number is 64. Which of the following is the correct electronic configuration of gadolinium?
General electronic configuration of actinoids is `(n-2)f^(1-14)(n - 1)d^(0-2)ns^2`.Which of the following actinoids have one electron in 6d orbital?
(i) U (Atomic no. 92)
(ii) Np (Atomic no.93)
(iii) Pu (Atomic no. 94)
(iv) Am (Atomic no. 95)
Although +3 is the characteristic oxidation state for lanthanoids but cerium also shows +4 oxidation state because:
(i) it has variable ionisation enthalpy
(ii) it has a tendency to attain noble gas configuration
(iii) it has a tendency to attain f 0 configuration
(iv) it resembles Pb4+
Although +3 oxidation states is the characteristic oxidation state of lanthanoids but cerium shows +4 oxidation state also. Why?
On the basis of Lanthanoid contraction, explain the following:
Radii of 4d and 5d block elements.
Zr (Z = 40) and Hf (Z = 72) have similar atomic and ionic radii because of ______.
Name an important alloy which contains some of the lanthanoid metals.
