English

Account for the following: Transition metals form alloys.

Advertisements
Advertisements

Questions

Account for the following:

Transition metals form alloys.

Explain why do transition metals form alloys among themselves.

Explain
Short Answer
Advertisements

Solution 1

Transition metals have very similar atomic sizes as a result one metal can easily replace the other metal from its lattice to form solid solution (alloy). Transition metals are also miscible with one another in the molten state. Thus, the molten state solution of two or more transition metals on cooling forms an alloy.

shaalaa.com

Solution 2

  1. Transition metals have very similar atomic sizes.
  2. Because of this similarity, one metal atom can easily replace another in the metal lattice.
  3. This forms a solid solution called an alloy.
  4. Transition metals are also miscible in their molten state, meaning they mix well when melted.
  5. Upon cooling, the molten mixture solidifies as an alloy.
  6. These alloys are usually hard and have high melting points.

Thus, the similar atomic size and good miscibility in the molten state lead transition metals to form alloys easily.

shaalaa.com
  Is there an error in this question or solution?
2021-2022 (March) Term 2 - Outside Delhi Set 1

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

The elements of 3d transition series are given as: Sc Ti V Cr Mn Fe Co

Answer the following: Which element shows only +3 oxidation state?


Why are Mn2+ compounds more stable than Fe2+ towards oxidation to their +3 state?


Following are the transition metal ions of 3d series:

Ti4+, V2+, Mn3+, Cr3+

(Atomic numbers: Ti = 22, V = 23, Mn = 25, Cr = 24)

Answer the following:

1) Which ion is most stable in an aqueous solution and why?

2) Which ion is a strong oxidising agent and why?

3) Which ion is colourless and why?


Out of \[\ce{Cu2Cl2}\] and \[\ce{CuCl2}\], which is more stable and why?


Although \[\ce{Cr^3+}\] and \[\ce{Co^2+}\] ions have same number of unpaired electrons but the magnetic moment of \[\ce{Cr^3+}\] is 3.87 B.M. and that of \[\ce{Co^2+}\] is 4.87 B.M. Why?


Match the properties given in Column I with the metals given in Column II.

  Column I (Property) Column II (Metal)
(i)  An element which can show +8 oxidation state (a) \[\ce{Mn}\]
(ii)  3d block element that can show (b) \[\ce{Cr}\]
  upto +7 oxidation state (c) \[\ce{Os}\]
(iii)  3d block element with highest melting point (d) \[\ce{Fe}\]

Answer the following question:

Which element of the first transition series has highest second ionisation enthalpy?


Identify the metal and justify your answer.

Carbonyl \[\ce{M(CO)5}\]


The orientation of an atomic orbital is governed by


Compare the general characteristics of the first series of the transition metals with those of the second and third series metals in the respective vertical columns. Give special emphasis on the following point:

Atomic sizes


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×